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lisabon 2012 [21]
3 years ago
13

The average marathon is 42 km long. If the average person can run the marathon with an average velocity of 2.57 m/s, how long wi

ll it take him to finish the race
Physics
1 answer:
deff fn [24]3 years ago
6 0

There's no such thing as an "average marathon".  The marathon run is a world athletic sport in which records are kept, and every marathon is the same distance.  The official distance of The Marathon is  42.195 km. 

Time = (distance covered) / (average speed).

Time = (42.195 km) / (2.57 m/s) = 16,418.29 seconds

                                                   =  4hrs 33min 38.29 sec

Note:
With no information given regarding the direction of any part of the
course, the solution must proceed in terms of speed, not velocity.
The question is written as if 'velocity' were a more formal, technical
word for 'speed', but such is not the case.  They are two different
things.

A foot race is a very awkward place to attempt a discussion in terms
of velocity. On a typical marathon course, the starting line and finish line
are in the same place.  Where that is true, the displacement of a runner
who completes the course is zero, and his average velocity is also zero.   

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bixtya [17]

Answer:

a) The velocity of the car is 7.02 m/s and the car is approaching to the police car as the frequency of the police car is increasing.

b) The frequency is 1404.08 Hz

Explanation:

If the police car is a stationary source, the frequency is:

f_{a} =(\frac{v+v_{c} }{v} )f_{s} (eq. 1)

fs = frequency of police car = 1200 Hz

fa = frequency of moving car as listener

v = speed of sound of air

vc = speed of moving car

If the police car is a stationary observer, the frequency is:

f_{L} =f_{a} (\frac{v}{v-v_{c} } )=(\frac{v+v_{c} }{v-v_{c} } )f_{s} (eq. 2)

Now,

fL = frequecy police car receives

fs = frequency police car as observer

a) The velocity of car is from eq. 2:

1250=1200(\frac{v+v_{c} }{v-v_{c} } )\\1250(v-v_{c} )=1200(v+v_{c} )\\v_{c} =\frac{50*344}{2450} =7.02m/s

b) Substitute eq. 1 in eq. 2:

f_{L} =(\frac{v+v_{p} }{v-v_{c} } )(\frac{v+v_{c} }{v-v_{p} } )f_{s} =(\frac{344+20}{344-7.02} )(\frac{344+7.02}{344-20} )*1200=1404.08Hz

7 0
3 years ago
Naturally occurring element X exists in three isotopic forms: X-28 (27.977 amu, 92.23% abundance), X-29 (28.976 amu, 4.67% abund
vova2212 [387]

Answer:

C. 28.09 amu

Explanation:

The natural occurring element exist in 3 isotopic forms: namely X-28 (27.977 amu, 92.23% abundance),  X-29 (28.976 amu, 4.67% abundance) and  X-30 (29.974 amu, 3.10% abundance).

The atomic weight of elements depends on the isotopic abundance. If you know the fractional abundance and the mass of the isotopes the atomic weight can be computed.

The atomic weight is computed as follows:

atomic weight = mass of X-28 × fractional abundance + mass of X-29 × fractional abundance + mass of  X-30 × fractional abundance

atomic weight = 27.977 × 0.9223 + 28.976 × 0.0467 + 29.974 ×  0.0310

atomic weight = 25.8031871 + 1.3531792 + 0.929194

atomic weight = 28.0855603 amu

To 2 decimal place atomic weight = 28.09 amu

6 0
3 years ago
How does a mirage occur in a deser?explain with a labelled diagram.​
Ronch [10]

Answer:

Mirages happen when the ground is very hot and the air is cool.

Explanation:

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When you see it from a distance, the different air masses colliding with each other act as a mirror.

8 0
2 years ago
Read 2 more answers
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natka813 [3]

Responder:

13,01 m / s

Explicación:

Paso uno:

datos dados

masa de la persona 1 m = 80 kg

velocidad de la persona 1 v = 9 m / s

masa de la persona 2 M = 55kg

velocidad de la persona 2 v =?

Segundo paso:

la expresión del impulso se da como

P = mv

para la primera persona, el impulso es

P = 80 * 9

P = 720N

Paso tres:

queremos que la segunda persona tenga el mismo impulso que la primera, por lo que la velocidad debe ser

720 = 55v

v = 720/55

v = 13,09

v = 13,01 m / s

Por lo tanto, la magnitud de la velocidad debe ser 13.01 m / s.

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3 years ago
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Galina-37 [17]

Answer:

100nm

Explanation:

Work=Force×distance

=20×5

=100nm

6 0
2 years ago
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