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e-lub [12.9K]
3 years ago
6

NaOH is an Arrhenius base because it increases the concentration of hydroxide ions when dissolved in solution.

Chemistry
2 answers:
Licemer1 [7]3 years ago
7 0

The answer is true, NaOH is and Arrhenius base.

sergey [27]3 years ago
6 0

<u>Answer:</u> The correct answer is True.

<u>Explanation:</u>

According to Arrhenius acid-base concept:

An acid is defined as the substance which releases hydrogen ions (H^+) when dissolved in water.

A base is defined as the substance which releases hydroxide ions (OH^-) when dissolved in water.

As, NaOH releases hydroxide ion when it is dissolved in water. Thus, it is considered as an Arrhenius base.

The reaction of ionization of NaOH is given by the equation.

NaOH(aq.)\rightarrow Na^+(aq.)+OH^-(aq.)

Hence, the given statement is True.

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Answer:

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Explanation:

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Which of the following changes would have no effect on the equilibrium position of the reaction below? 2 NOBR (g) 2 NO (g)+ Br2
nasty-shy [4]

Answer:

D) cutting the concentrations of both NOBr and NO in half

Explanation:

The equilibrium reaction given in the question is as follows -

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The equilibrium constant for the above reaction can be written as -

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Therefore from the condition given in the question , the changes that will not affect the equilibrium will be , reducing the concentration of both NOBr and NO to half ,

Hence ,

the new concentrations are as follows -

[ NoBr ] ' = 1/2 [ NoBr ]

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Hence the new equilibrium constant equation can be written as -

K ' = [ NO ] ' ² [ Br₂ ] / [ NOBr ]  ' ²

Substituting the new concentration terms ,

K ' = 1/2  [ NO ] ² [ Br₂ ] / 1/2 [ NoBr ]  ²

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The value of 1 / 4 in the numerator and the denominator is cancelled -

K ' =   [ NO ] ² [ Br₂ ] /  [ NoBr ]  ²

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5 0
4 years ago
What is the value of the equilibrium constant for this redox reaction?
aivan3 [116]
Correct  answer: Option D, <span>K = 5.04 × 10^52
</span>
Reason:
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Also, Ecell = <span>+1.56 v

Therefore, 1.56 = </span>\frac{0.0592}{2}log(K)
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