1.T
2.F
3.T
I think I think Im not complety sure sorry
Answer:
The density of this liquid is 0.320 kg/L
Explanation:
Given:
Volume of the Liquid = 0.820 L
Mass of the liquid = 2.56 kg.
To Find:
The density of the liquid in kg/L
Solution:
Density is the mass occupied by the substance in unit volume. This density is essential determining whether the substance floats or sinks. Greek letter(rho) is used to denote density
The equation of for density is


where m is the mass
v is the volume
On substituting the given values


Answer:
D
Explanation:
A beaker can be used for boiling coz it can withstand high temperatures.
It can be used for measuring the volume of a solid indirectly by measuring the displacement of a liquid.
It can as well be used for mixing coz it flat bottomed
Answer: The partial pressure of the Kr is 320 mm Hg.
Explanation:
According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as

where,
= partial pressure of component A
= mole fraction of A
= total pressure
mole fraction of Krypton = 

Thus partial pressure of the Kr is 320 mm Hg
12 atm is the new pressure of the air‑fuel mixture when A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600 ml at 1.0atm and final volume of 50 ml.
Explanation:
Data given:
The air fuel mixture is assumed to be having ideal behaviour
initial volume of gaseous air fuel mixture V1 = 600 ml
initial pressure of gaseous air fuel mixture P1= 1 atm
final volume when piston is removed, V2= 50 ml
final pressure of the gaseous air mixture, P2 = ?
Applying the Boyle's Law,
P1V1 = P2V2
rearranging the equation:
P2 = 
putting the value in the equation,
P2 = 
P2 = 12 atm
the pressure is increased to 12 atm when volume is reduced to 50 ml.