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katrin2010 [14]
3 years ago
15

Someone help w one of these questions. Or if you know all of them surely help.

Chemistry
1 answer:
fenix001 [56]3 years ago
5 0

Answer:

1 A true

B False

C not sure about it False

D False

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True or False to show whether you think each statement is true
romanna [79]
1.T

2.F

3.T
I think I think Im not complety sure sorry
5 0
3 years ago
Read 2 more answers
A liquid that occupies a volume of 0.820 L has a mass of 2.56 kg.
user100 [1]

Answer:

The density of this liquid is 0.320 kg/L

Explanation:

Given:

Volume of the Liquid =  0.820 L

Mass of the liquid  = 2.56 kg.

To Find:

The density of the liquid in  kg/L

Solution:

Density is the mass occupied by the substance in unit volume. This density is essential determining whether the substance floats or sinks. Greek letter(rho) is used to denote density

The equation of for density is

Density = \frac{mass}{volume}

\rho = \frac{m}{v}

where m is the mass

v is the volume

On substituting the given values

\rho = \frac{0.820 }{2.56}

\rho = 0.320 kg/L

7 0
3 years ago
2. Which type of glassware is used for general mixing, measuring and
ella [17]

Answer:

D

Explanation:

A beaker can be used for boiling coz it can withstand high temperatures.

It can be used for measuring the volume of a solid indirectly by measuring the displacement of a liquid.

It can as well be used for mixing coz it flat bottomed

5 0
3 years ago
A mixture of 1.20 mols He, 2.40 mols Ne, 4.80 mols Kr, and 0.60 mols Ar has a total pressure of 600.0 mm Hg. What is the partial
Juliette [100K]

Answer: The partial pressure of the Kr is 320 mm Hg.

Explanation:

According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as

p_A=x_A\times P_{total}

where, p_A = partial pressure of component A

x_A = mole fraction of A

P_{total} = total pressure

mole fraction of Krypton = \frac{\text {Moles of Kr}}{\text {total moles}}=\frac{4.80}{1.20+2.40+4.80+0.60}=0.53

p_{Kr}=0.53\times 600mmHg=320mmHg

Thus partial pressure of the Kr is 320 mm Hg

8 0
3 years ago
A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600.mL at 1.0atm. To prepare for ignition of
Ket [755]

12 atm is the new pressure of the air‑fuel mixture when A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600 ml at 1.0atm and final volume of 50 ml.

Explanation:

Data given:

The air fuel mixture is assumed to be having ideal behaviour

initial volume of gaseous air fuel mixture V1 = 600 ml

initial pressure of gaseous air fuel mixture P1= 1 atm

final volume when piston is removed, V2= 50 ml

final pressure of the gaseous air mixture, P2 = ?

Applying the Boyle's Law,

P1V1 = P2V2

rearranging the equation:

P2 = \frac{P1V1}{V2}

putting the value in the equation,

P2 = \frac{600 X 1}{50}

P2 = 12 atm

the pressure is increased to 12 atm when volume is reduced to 50 ml.

7 0
3 years ago
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