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Mariulka [41]
3 years ago
11

What is the value of the equilibrium constant for this redox reaction?

Chemistry
2 answers:
aivan3 [116]3 years ago
8 0
Correct  answer: Option D, <span>K = 5.04 × 10^52
</span>
Reason:
We know that, 
Ecell = \frac{0.0592}{n}log(K),
where n = number of electrons = 2 (in present case)
K = equilibrium constant.

Also, Ecell = <span>+1.56 v

Therefore, 1.56 = </span>\frac{0.0592}{2}log(K)
Therefore, log (K) = 52.703
Therefore,  K = 5.04 X 10^52


nignag [31]3 years ago
3 0
D for all the plato homies
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