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3 years ago

Number of atoms in calcium carbonate

Chemistry

1 answer:

lakkis [162]3 years ago

3 0

Answer:

5 Atoms

Explanation

We have one atom of Calcium, One Atom of Carbon and three of Oxygen

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Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring 12.0 ft×15.0 ft×8.60ft.

garik1379 [7]

Given:

Dimensions of the room= 12 ft * 15 ft * 8.60 ft

To determine:

The amount of HCN that gives the lethal dose in the room with the given dimensions

Explanation:

As per the World Health Organization, the lethal dose of HCN is around 300 ppm

300 ppm = 300 mg of HCN/ kg of inhaled air

Volume of air = volume of room = 12 * 15 *8.6 = 1548 ft³

Now, 1 ft³ = 28316.8 cm³

Therefore, the calculated volume of air corresponds to:

1548 * 28316.8 = 4.383 * 10⁷ cm3

Density of air (at room temperature 25 C) = 0.00118 g/cm3

Thus mass of air corresponding to the calculated volume is

Mass = Density * volume = 0.00118 g/cm3 * 4.383 * 10⁷ cm3

= 5.172*10⁴ g = 51.72 kg

Lethal amount of HCN corresponding to 51.72 kg of air would be.

= 51.72 kg air* 300 mg of HCN/1 kg air = 15516 mg

Ans: Lethal dose of HCN = 15.5 g

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2 years ago

A procedure calls for the bromination of 12 mmol of trans‑cinnamic acid with 12 mmol of Br 2 in glacial acetic acid solvent. Sel

SashulF [63]

Answer: The yield of dibromide product will be approximately one‑half of the expected yield.

Explanation:

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2 years ago

WILL GIVE BRAINLIEST!!!

Hoochie [10]

Hey there!:

ΔTf = Kf * m

Molar mass glucose = 180 g/mol

number of moles glucose:

n = mass of solute / molar mass

n = 21.5 / 180

n = 0.119 moles glucose

Amount of solvent in kg = 255/1000 = 0.255 Kg

Molality = number of moles / solvent

m = 0.119 / 0.255

m = 0.466 moles/kg

Kf for water = - 1.86 ºC/*m

Therefore:

ΔTf = Kf * m

ΔTf = (-1,86) * 0.466

ΔTf = -0.86676 ºC

hope this helps!

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3 years ago

Read 2 more answers

What quantity of sodium azide in grams is required to fill a 56.0 liters air bag with nitrogen gas at 1.00 atm and exactly 0 °C:

Margarita [4]

Answer:

108.6 g

Explanation:

2NaN₃(s) → 2Na(s) + 3N₂(g)

First we use the PV=nRT formula to calculate the number of nitrogen moles:

P = 1.00 atm

V = 56.0 L

n = ?

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = 0 °C ⇒ 0 + 273.2 = 273.2 K

Inputting the data:

1.00 atm * 56.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 273.2 K

n = 2.5 mol

Then we convert 2.5 moles of N₂ into moles of NaN₃, using the stoichiometric coefficients of the balanced reaction:

2.5 mol N₂ * $\frac{2molNaN_3}{3molN_2}$ = 1.67 mol NaN₃

Finally we convert 1.67 moles of NaN₃ into grams, using its molar mass:

1.67 mol * 65 g/mol = 108.6 g

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You're leaving a carnival and you're pumped because a clown just handed you a red, helium- filled balloon. But then, something t

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Because the helium inside it is lighter than air , hence it rises up
The balloon from our breath contains carbon dioxide which is heavier than air so it doesn’t rise

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