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horsena [70]
4 years ago
10

(a) What was Jennifer’s gross pay for the year?

Mathematics
1 answer:
GarryVolchara [31]4 years ago
4 0
You ever get the answers I need them
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What is the measure of MBT?
s344n2d4d5 [400]

\\ \sf\longmapsto 17x-6=5x+18

\\ \sf\longmapsto 17x-5x=18+6

\\ \sf\longmapsto 12x=24

\\ \sf\longmapsto x=\dfrac{24}{12}

\\ \sf\longmapsto x=2

Now

\\ \sf\longmapsto \angle{MBT}

\\ \sf\longmapsto 5x+18

\\ \sf\longmapsto 5(2)+18

\\ \sf\longmapsto 10+18

\\ \sf\longmapsto 28

7 0
3 years ago
Read 2 more answers
Find the critical points of the surface f(x, y) = x3 - 6xy + y3 and determine their nature.​
Vedmedyk [2.9K]

Compute the gradient of f.

\nabla f(x,y) = \left\langle 3x^2 - 6y, -6x + 3y^2\right\rangle

Set this equal to the zero vector and solve for the critical points.

3x^2-6y = 0 \implies x^2 = 2y

-6x+3y^2=0 \implies y^2 = 2x \implies y = \pm\sqrt{2x}

\implies x^2 = \pm2\sqrt{2x}

\implies x^4 = 8x

\implies x^4 - 8x = 0

\implies x (x-2) (x^2 + 2x + 4) = 0

\implies x = 0 \text{ or } x-2 = 0 \text{ or } x^2 + 2x + 4 = 0

\implies x = 0 \text{ or } x = 2 \text{ or } (x+1)^2 + 3 = 0

The last case has no real solution, so we can ignore it.

Now,

x=0 \implies 0^2 = 2y \implies y=0

x=2 \implies 2^2 = 2y \implies y=2

so we have two critical points (0, 0) and (2, 2).

Compute the Hessian matrix (i.e. Jacobian of the gradient).

H(x,y) = \begin{bmatrix} 6x & -6 \\ -6 & 6y \end{bmatrix}

Check the sign of the determinant of the Hessian at each of the critical points.

\det H(0,0) = \begin{vmatrix} 0 & -6 \\ -6 & 0 \end{vmatrix} = -36 < 0

which indicates a saddle point at (0, 0);

\det H(2,2) = \begin{vmatrix} 12 & -6 \\ -6 & 12 \end{vmatrix} = 108 > 0

We also have f_{xx}(2,2) = 12 > 0, which together indicate a local minimum at (2, 2).

3 0
2 years ago
Find the rule the pattern is using 4,20,100,50
Rudik [331]
If the last number is supposed to be 500 then the pattern is times 5.
4*5=20
20*5=100
100*5=500
6 0
3 years ago
Humans have a normal body temperature of 98.6°F. A temperature, x, that differs from normal by at least 2°F is considered unheal
Alecsey [184]

Answer:

x\geq100.6 and x\leq 96.6

Step-by-step explanation:

It is given that the normal body temperature is 98.6^\circ F.

A temperature 'x' that differs from normal by at least 2^\circ F is considered unhealthy. So the inequality to represent such situation is,

\left | x-98.6 \right |\geq 2

It can be further written as,

x-98.6\geq 2 and x-98.6\leq -2

x\geq (98.6+2) and x \leq(-2+98.6)

x\geq100.6 and x\leq 96.6

So the inequality to represent such condition is x\geq100.6 and x\leq 96.6 .

5 0
3 years ago
Read 2 more answers
What time is 2 1/2 hours before 1 a.m.
AlekseyPX
1 1/2 hours before 12:00 am, which is half an hour before 11:00 pm, which is 10:30 pm
3 0
4 years ago
Read 2 more answers
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