the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
You go through and square each term in the parentheses
(12a^2b^6)^2 = (12)^2(a^2)^2(b^6)^2 =
144a^4b^12
Answer:
18.0
Step-by-step explanation:
==>Given:
Triangle with sides, 16, 30, and x, and a measure of an angle corresponding to x = 30°
==>Required:
Value of x to the nearest tenth
==>Solution:
Using the Cosine rule: c² = a² + b² - 2abcos(C)
Let c = x,
a = 16
b = 30
C = 30°
Thus,
c² = 16² + 30² - 2*16*30*cos 30°
c² = 256 + 900 - 960 * 0.8660
c² = 1,156 - 831.36
c² = 324.64
c = √324.64
c = 18.017769
x ≈ 18.0 (rounded to nearest tenth)
Step-by-step explanation:
answer is in the above picture
This is the concept of relative speed; We are required to calculate the speed of the car and the bicycle.
Distance between the car and Bicycle=374 miles
Time they met=5.5 hr
Speed traveled by bicycle=x
Speed traveled by car=x+33.4334
Relative speed=x+(x+33.4334)=(2x+33.4334) mph
Distance=speed*time
374=(2x+33.4334)*5.5
374=11x+183.8837
collecting like term we get:
374-183.8837=11x
11x=190.1163
thus;
x=(190.1163)/(11)
x=17.2833 mph
thus the speed of the bicycle was x=17.2833 mph
The speed of the car was (x+33.4334)=(17.2833+33.4334)=50.7167 mph
