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I am Lyosha [343]
2 years ago
8

What is the measure of angle A?

Mathematics
2 answers:
bogdanovich [222]2 years ago
5 0

Answer:

actual answer is 77.32 !

Step-by-step explanation:


SSSSS [86.1K]2 years ago
4 0

The answer is indeed "77.32"

I just took the quiz :) Hope I could help!

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Write the following using algebraic notation, using the letter x for any
lbvjy [14]

9514 1404 393

Answer:

  2(x+1)

Step-by-step explanation:

  x . . . I think of a number

  x +1 . . . add 1

  2(x +1) . . . double the result

4 0
3 years ago
Complete the equation, and tell which property you used.<br><br> 8 x (14+7) = _________+ (8 x 7)
melamori03 [73]
By distributive property, 8 x (14 + 7) = (8 x 14) + (8 x 7)
8 0
3 years ago
The expression below represents the number of bacteria in a petri dish after t hours. Interpret the meaning of the expression.
konstantin123 [22]

The answer is B) The initial number of bacteria is 57, and the growth rate is 31% per hour.


The expression shown is an <em>exponential expression</em>.  An exponential expression usually takes the form ab^{x}, as this one does.  A represents the <em>initial value</em>, in this case-the initial number of bacteria.  B represents the <em>growth rate</em>.  When it is an increasing growth rate, it will begin with 1, because it will have everything it had before, plus the percent increase, the decimal portion.  In this case, a=57, and b=0.31.


Hope this makes sense!

3 0
3 years ago
Square root of 9/100
timama [110]
\sqrt{ \frac{9}{100} }
=\frac{3}{10}
5 0
3 years ago
Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.
Sindrei [870]

Answer:

a) P(X=3) = 0.1

b) P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

c) P(X=4) = 0.3

d) P(X=0) = 0.2

e) E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

f) E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

Step-by-step explanation:

We have the following distribution

x      0     1     2   3   4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

P(X=3) = 0.1

Part b

We want this probability:

P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

Part c

For this case we want this probability:

P(X=4) = 0.3

Part d

P(X=0) = 0.2

Part e

We can find the mean with this formula:

E(X)= \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

Part f

We can find the second moment with this formula

E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

4 0
3 years ago
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