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I am Lyosha [343]
3 years ago
8

What is the measure of angle A?

Mathematics
2 answers:
bogdanovich [222]3 years ago
5 0

Answer:

actual answer is 77.32 !

Step-by-step explanation:


SSSSS [86.1K]3 years ago
4 0

The answer is indeed "77.32"

I just took the quiz :) Hope I could help!

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Select the correct answer.
sineoko [7]

Answer:

A

Step-by-step explanation:

The plus 7 at the end will shift the graph 7 units up. Replace y with f(x).

Then we have g(x) = f(x) + 7. Adding 7 to y = f(x) will increase the y value by 7.

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3 years ago
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Solve 4x + 11 = k for x.
ehidna [41]

4x + 11 = k
4x = k - 11
x =  \frac{k - 11}{4}
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3 years ago
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(I don't usually ask for help on Brainly, but I really suck at Radicals and I need help.
Artemon [7]
My first answer.  Lots of parts for five minutes. Took me that long to decode the question.  It looks like your multiplying where you're taking roots.


(\sqrt[4]{7})^5 = (7^{\frac 1 4})^5 = 7^{\frac 5 4}


<span>Choice A.  Next
</span>
(3^{2/3})^{1/6} = 3^{ \frac 2 3 \times \frac 1 6 } = 3^{\frac 1 9} = \sqrt[9]{ 3} &#10;&#10;&#10;

Choice B. 

\dfrac {2^{3/4} } {2 ^{1/2} }  = 2^{3/4 - 1/2} = 2^{1/4} = \sqrt[4] {2}&#10;


Choice C






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3 years ago
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Is anyone able to figure this out, I can't do this
katrin [286]

Answer:

C. √2 - 1

Step-by-step explanation:

If we draw a square from the center of the large circle to the center of one of the small circles, we can see that the sides of the square are equal to the radius of the small circle (see attached diagram)

Let r = the radius of the small circle

Using Pythagoras' Theorem a^2+b^2=c^2

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

to find the diagonal of the square:

\implies r^2 + r^2 = c^2

\implies 2r^2 = c^2

\implies c=\sqrt{2r^2}

So the diagonal of the square = \sqrt{2r^2}

We are told that the radius of the large circle is 1:

⇒ Diagonal of square + r = 1

\implies \sqrt{2r^2}+r=1

\implies \sqrt{2r^2}=1-r

\implies 2r^2=(1-r)^2

\implies 2r^2=1-2r+r^2

\implies r^2+2r-1=0

Using the quadratic formula to calculate r:

\implies r=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

\implies r=\dfrac{-2\pm\sqrt{2^2-4(1)(-1)}}{2(1)}

\implies r=\dfrac{-2\pm\sqrt{8}}{2}

\implies r=-1\pm\sqrt{2}

As distance is positive, r=-1+\sqrt{2}=\sqrt{2}-1  only

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2 years ago
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8. There are 3 water slides in the park, arranged from shortest to tallest. The
Valentin [98]

Answer:

27

Step-by-step explanation:

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