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3 years ago

Find the sum of the measures of the interior angles of the figure.

Mathematics

1 answer:

Ivahew [28]3 years ago

4 0

Step-by-step explanation:

Given figure is of HEXAGON.

the sum of the measures of the interior angles of a hexagon

$= \frac{(6 - 2) \times 180 \degree}{6} \times 6 \\ \\ = {4 \times 30 \degree} \times 6 \\ \\ = 720 \degree$

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For every car you sell, you get a 6% commission. IF your total sales for the month is $125,650, what is your commission?

Lera25 [3.4K]

Let
x= total cost of cars
y= total commission paid out for all cars sold

6%= 6/100 = .06

Set up an equation:
y= .06(x)

Given: x= $125,650

substitute into the y= .06(x)

multiply $125,650 by .06.

The answers would be: 7539

hope this helped :)

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2 years ago

Read 2 more answers

Find the exact value of sec (–660)°

Nostrana [21]

Add full rotations of 360° degree until the angle of between 0° and 360°.
Sec (60)
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2 years ago

Tina got a haircut, and her hair is still at least 15 inches long, write and graph an inequality

ivanzaharov [21]

The inequality is:

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3 years ago

Instead of using the values {1,2,3,4,5,6}

tiny-mole [99]

Answer:

1/36

Step-by-step explanation:

it is the exact same as if both your dice had the numbers {1,2,3,4,5,6}

you said the SUM of the dice that is indicates the answer of the addition of two (or for that matter more) numbers,... the only numbers that would sum 2 is 1+1,... and because you only have two ones (one per die) the answer is the same as if they where die with normal numbers,...

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2 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

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2 years ago