2.33 is the right answer.
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a 25.0ml dsmplr og 0.105M HCI was titrated with 31.5ml of NaOH. What is the concentration of the NaOH I got 0.0834M am I correct HCI + NaOH -----> H20 + NaCl 25.0ml HCI x 1L/1000mlx0.105 mol HCI/1L HCI X 1 mol NaOH/ I mol HCI = 0.0834M
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Answer:
Explanation:
1. Calculate the molar mass of ammonia
1 N = 1 × 14.01 g = 14.01 g
3 H = 3 × 1.008 g = <u> 3.024 </u>
TOTAL = 17.03 g
2. Calculate the mass of hydrogen
So, there are 3.024 g of H in17.03 g of NH₃.
The conversion factor is either
We want to find grams of H, so we choose the one with grams of H on top.