Since the ethanol has a density of 0.800 g/mL, the mass of the ethanol is 180 grams.
<u>Given the following data:</u>
- Volume of ethanol = 225 mL
- Density of lead ball = 0.800 g/mL.
To find the mass of the ethanol;
Density can be defined as mass all over the volume of an object.
Mathematically, the density of a substance is given by the formula;
Making mass the subject of formula, we have;
Substituting the given parameters into the formula, we have;
<em>Mass of ethanol </em><em>=</em><em> 180 grams.</em>
Read more: brainly.com/question/18320053
Answer:
Good.
Explanation:
djsbeusjsbwjdkdjxjwnsjdjd
The given concentration of boric acid = 0.0500 M
Required volume of the solution = 2 L
Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.
Calculating the moles of 0.0500 M boric acid present in 2 L solution:
Converting moles of boric acid to mass:
Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.
Answer:
1s² 2s²2p³
Explanation:
If the atom has seven electrons, it is Element 7 (nitrogen).
In the Periodic Table, you count the electrons in all the subshells up to
No. 7.
In the first Period, you have filled the 1s level (2 electrons).
In the second Period, you have filled the 2s subshell (2 electrons) and put three electrons in the 2p subshell.
Thus, the electron configuration is
1s² 2s²2p³
Note how the superscripts tell you the number of electrons in each subshell: <em>2 + 2 + 3 = 7</em>.
Explanation:
Expression for the coefficient of thermal expansion is as follows.
where, V = initial volume
= Final volume - initial volume
= (712.6 - 873.6) 
= -161
Now, we will calculate the change in temperature as follows.
= Final temperature - Initial temperature
= (10 + 273) K - (70 + 273) K
= 283 K - 343 K
= -60 K
Substituting these values into the equation as follows.
= 0.00307 
It is known that for non-ideal gases the value of alpha is 0.366% which is 0.00366 per Kelvin. As it is close to our result, hence the given sample of gas is a non-ideal gas.
