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olga_2 [115]
2 years ago
10

In this lab, you will figure out who was guilty of the classroom food mess by determining which macromolecules are present in th

e mystery food sample.
Rephrase this statement as a scientific question you can answer through investigation.
PLEASE I NEED UR HELP!!!!! WORTH 100 POINTS
Chemistry
1 answer:
natta225 [31]2 years ago
3 0

The scientific question that can be answered through investigation will be:

<em>"Which of the four types of macromolecules, and in which proportions, are present in the food sample?"</em>

<h3>What is scientific question ?</h3>

A scientific question is a question that may lead to a hypothesis and help us in. answering (or figuring out) the reason for some observation.

A scientific question simply means a question where a researcher designs a question in order to get an answer to a particular investigation.

According to this question,

Since the researcher wants to know the person responsible for the classroom good mess by determining which macromolecules are present in the mystery food sample, then the question will be<em> "Which of the four types of macromolecules, and in which proportions, are present in the food sample?"</em>

Learn more about experiments here ;

brainly.com/question/13271957

#SPJ1

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The answer is Hg.

Explanation:

Symbol for Mercury is Hg.

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When 12 moles of o2 react with 1.1 mole of c10h8 what is the limiting reactant?
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1.1   moles   of C10H8  is the  limiting  reagent  in   the  reaction between   reaction  C10H8   and   O2
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C10H8  +  12O2  ---->  10CO2   + 4H2O

C10H8  is  the  limiting   reagent   since   1.1  moles  of  C10H8  is  totally   consumed   during  the  reaction
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3. A mechanical pencil has a mass of 47.4 grams. The volume of the pencil is 15.8 cubic centimeters. What is the density of the
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Answer:

<h3>The answer is 3 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{47.4}{15.8}  \\

We have the final answer as

<h3>3 g/cm³</h3>

Hope this helps you

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PLEASE HELP!! Thanks! How much heat (in kJ) is required to warm 13.0 g of ice, initially at -10.0 ∘C, to steam at 111.0 ∘C? The
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Answer:

Approximately 39.7 kJ.

Assumptions: the specific heat capacity of water is \rm 4.182\; J \cdot mol^{-1}, the melting point of water is \rm 0\, ^{\circ} C, and that the boiling point of water is \rm 100 \,^{\circ} C.

Explanation:

It takes five steps to convert 13.0 grams of \rm \text{-}10.0\, ^{\circ}C ice to steam at \rm 111.0\,^{\circ}C.

  • Step one: heat the 13.0 gram of ice from \rm \text{-}10.0\, ^{\circ}C to \rm 0\,^{\circ}C. The change in temperature would be \rm 10.0\,^{\circ}C.
  • Step two: supply the heat of fusion to convert that 13.0 gram of ice to water.
  • Step three: heat the 13.0 gram of water from\rm 0\,^{\circ}C to \rm 100\,^{\circ}C. The change in temperature would be \rm 100\,^{\circ}C.
  • Step four: supply the heat of vaporization to convert that 13.0 gram of water to steam.
  • Step five: heat the 13.0 gram of steam from\rm 100\,^{\circ}C to \rm 111.0\,^{\circ}C. The change in temperature would be \rm 11.0\,^{\circ}C.

<h3>Energy required for step one, three, and five</h3>

The following equation gives the amount of energy Q required to raise the temperature of an object  by a \Delta T:

Q = c \cdot m \cdot \Delta T.

In this equation,

  • c is the specific heat of this substance,
  • m is the mass of the substance, and
  • \Delta T is the change in the temperature of the object.

Assume that there's no mass loss in this whole process. The value of m would stay the same at 13.0\; \rm g.

\begin{aligned}& &&\text{Energy required for raising temperature} \cr &=&& c(\text{Ice}) \cdot m \cdot \Delta(\text{Ice}) \cr & && + c(\text{Water}) \cdot m \cdot \Delta(\text{Water})\cr & && + c(\text{Steam}) \cdot m \cdot \Delta(\text{Steam}) \cr & = && (2.09 \times 13.0 \times 10) \cr & && + (4.182 \times 13.0 \times 100) \cr & &&+ ( 2.01 \times 13.0 \times 10) \cr & = && 5969.6\;\rm J \cr & = && 5.969\; \rm kJ\end{aligned}.

<h3>Energy required for step two and four</h3>

The equations for the energy of fusion and energy of vaporization are quite similar:

E(\text{Fusion}) = n \cdot \Delta H_\text{Fusion}.

E(\text{Vaporization}) = n \cdot \Delta H_\text{Vaporization}.

where n is the number of moles of the substance.

Look up the relative atomic mass of oxygen and hydrogen from a modern periodic table:

  • H: 1.008,
  • O: 15.999.

Hence the molar mass of water:

M(\rm H_2O) = 2\times 1.008 + 15.999 = 18.015\; g \cdot mol^{-1}.

Number of moles of \rm H_2O molecules in \rm 13.0\; g:

\displaystyle n = \frac{m}{M} \approx 0.721621\; \rm mol.

\begin{aligned}& &&\text{Energy required for phase changes} \cr &=&& n \cdot \Delta H_\text{Fusion} \cr & &&+n \cdot \Delta H_\text{Vaporization} \cr & = &&0.721621 \times 6.02 + 0.721621 \times 40.7 \cr & = &&33.7\; \rm kJ \end{aligned}

<h3>Energy required for all five steps, combined</h3>

5.969\; \rm kJ + 33.7\; \rm kJ \approx 39.7\; \rm kJ.

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What is an elastic collison?
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