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3 years ago

11

Given that the points (-3, 2) and (1, 2) are vertices of a rectangle, what two sets of coordinates could form the other two vert

ices?

1 answer:

polet [3.4K]3 years ago

3 0

-3,2 means on quadrant 4 and 1,2 is in quadrant 1

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Use the figure to the right to find the missing lengths of the triangle.

pychu [463]

To find AB(x) and BC(y), you can do(there are multiple ways you can do this):

tan A = $\frac{y}{7}$

tan 60° = $\frac{y}{7}$ or (tan 60°) · 7 = y

tan 60° = $\frac{\frac{\sqrt{3} }{2} }{ \frac{1}{2} } = \sqrt{3}$

√3 · 7 = y

7√3 cm = y

sin B = $\frac{7}{x}$

sin 30° = $\frac{7}{x}$ or $x= \frac{7}{sin 30}$

sin 30° = $\frac{\frac{1}{2} }{1}$ = $\frac{1}{2}$

x = $\frac{7}{\frac{1}{2} } = 14$

x = 14 cm

AB = 14cm

BC = 7√3 cm

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3 years ago

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belka [17]

The answer is x=2 i hope this helps !!

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3 years ago

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Ryan can text 22 words in 4 minutes. At this rate, how many words could he text in 12 minutes? Fill out the table of equivalent

aleksandrvk [35]

The answer would be 66
Explanation: first you have to divide the minutes so 12 divided by 4 equals 3 so you would take the three and multiply that by 22. So 22x3 is equal to 66

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3 years ago

8. Mario walks 7 blocks from his home to

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Drag the tiles to the correct boxes to complete the palrs.

Brut [27]

Answer:

(f+g)(2) = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

$f(x) = 2x + 3$

$g(x) = x - 1$

(f+g)(2)

$(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2$

At $x = 2$

$(f+g)(2) = 3(2) - 2 = 6 - 2 = 4$

Then

(f+g)(2) = 4

(f-g)(4)

$(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4$

At x = 4

$(f-g)(4) = 4 + 4 = 8$

Then

(f-g)(4) = 8

(f ÷g)(2)

$(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}$

At x = 2

$(f \div g)(2) = \frac{7}{1} = 7$

Then

(f ÷g)(2) = 7

(f x g)(1)

$(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3$

Then

$(f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0$

So

(f x g)(1) = 0

4 0

3 years ago