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Anna [14]
3 years ago
8

Team tool bella canoed 15 3/4 miles in 5 1/4 hours. What was their average rate of speed in mph

Mathematics
2 answers:
Alona [7]3 years ago
8 0

Answer:  The average rate of speed is 3 miles per hour.

Step-by-step explanation:  Given that the team tool bella canoed 15\dfrac{3}{4} miles in 5\dfrac{1}{4} hours. We are given to find the average rate of speed in miles per hour (mph).

We will be using unitary method to solve the given problem.

Now,

15\dfrac{3}{4}=\dfrac{63}{4},~~~~~5\dfrac{1}{4}=\dfrac{21}{4}.

According to the question,

In \dfrac{21}{4} hours, number of miles canoed by the team is

=\dfrac{63}{4}~\textup{miles}.

Therefore, in 1 hour, number of miles canoed by the team is given by

\dfrac{\frac{63}{4}}{\frac{21}{4}}=\dfrac{63}{4}\times \dfrac{4}{21}=3~\textup{miles}.

Thus, the average rate of speed is 3 miles per hour.

yarga [219]3 years ago
6 0
Team Tool Bella's average rate was 3 miles per hour.
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Answer:

Written Below.

Step-by-step explanation:

A system of linear equations has one solution when the graphs intersect at a point. A system of linear equations has no solution when the graphs are parallel. A system of linear equations has infinite solutions when the graphs are the exact same line.

(This uses graphing.)

Sidenote: I hope this helps! :)

7 0
3 years ago
What is the area of the following trapezoid in square feet?
tangare [24]

Answer:

82.5 ft²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = \frac{1}{2} h (b₁ + b₂)

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 7.5, b₁ = 7 and b₂ = 15 , then

A = \frac{1}{2} × 7.5 × (7 + 15) = 0.5 × 7.5 × 22 = 82.5 ft²

4 0
2 years ago
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Simply 4 square root of 45
maksim [4K]
Answer : 12 square root 5

4 square root 45
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3 0
3 years ago
Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

3 0
2 years ago
Read 2 more answers
I need help asap with this
tatyana61 [14]

Answer:

51°

Step-by-step explanation:

Given

<QPR = 39°

<PQR = 90° ( inscribed angle in semi circle)

Now

<QPR + <PQR + <PRQ = 180° { being sum of angles of triangle)

39° + 90° + <PRQ = 180°

<PRQ = 180° - 39° - 90°

<PRQ = 51°

Hope it will help :)

5 0
2 years ago
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