F(of spring)=230x=ma=3.5(5)=17.5=230x; x=0.07m.
Answer:
I attached a PFD with the answer to your question and roughly 50 others involving acceleration and how to calculate it. This PDF gives you the answers to all the question whilst showing you an in-depth explanation on how they got the answer. Hopefully that helps
Explanation:
May I have brainliest please? :)
F=-kx
so multiple the two numbers together and put a negative sign in front
F=-19.25
We know that force <span>for a linear spring is equal to F=kx. Since energy is the potential to do work, and the spring is assumed to be perfectly elastic. Work can be written as:
W = F (integral sign) d</span>x
Therefore,
<span>W=k(Δx<span>)^2 / 2
W = F </span></span>Δx / 2
<span>W = 120 (2.0) / 2
W = 120
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