I = mΔv
I = 2.5 x (7.5 - 0) = 18.75 kg.m/s
Now, considering that the ball´s initial velocity was zero, we have:
1.45 x 0 + 2.5 x 7.5 = 1.45 x V
1.45V = 18.75
V = 12.93 m/s
(a) The work done by the person is 18.83465 kJ.
(b) The average power performed by the person during the walk is 51.4 W.
(c) The amount of food calories burnt is 4.5 Cal.
<h3>Work done by the person</h3>
The work done by the person is calculated as follows;
W = Fd
W = mgh
W = (89.2 x 9.8) x (0.162 x 133)
W = 18,834.65 J
W = 18.83465 kJ
<h3>Average power of the person</h3>
P = Fv
where;
v = (d)/t
v = (133 x 0.162)/(6 x 60 + 6)
v = (133 x 0.162)/(366)
v = 0.0588 m/s
P = (89.2 x 9.8) x 0.0588
P = 51.4 W
<h3>Amount of food calories burnt</h3>
4.1868 kJ = 1 Cal
18.83465 kJ = ?
= 4.5 Cal
Learn more about work done here: brainly.com/question/8119756
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