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3 years ago

Refraction or the bending of waves takes place when a light wave changes A) color. B) frequency. C) intensity. D) speed.

Physics

2 answers:

dolphi86 [110]3 years ago

8 0

Answer:

Option (D)

Explanation:

Refraction is defined as the process by which a wave changes its direction of propagation and bends towards the normal when moves from a rarer medium to a denser medium. The light after entering the new medium bends towards the normal. This process takes place due to the change in the wave speed and also due to the change in its wavelength.

As the waves enter a denser medium (such as glass) from the rarer medium (such as air), the wave speed decreases and so its wavelength also decreases. The speed and wavelength here are directly proportional to each other. It is because there are more particles in the denser medium that obstructs the direction of wave propagation.

Thus, the correct answer is an option (D).

DENIUS [597]3 years ago

6 0

The answer is D. speed

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The universe was 5 percent its current size when light left objects observed now at redshift of ______________

Nuetrik [128]

The redshift of distant galaxy are larger than those of closer galaxies, which indicates that the galaxy is receding at a faster rate.

The Universe was 5 percent its current size when light left objects now at redshift of <u>19</u>.

Reasons:

The size of the universe represented as a scale factor with relation to the redshift can be presented as follows;

$\displaystyle \frac{a}{a_0} =\mathbf{ \frac{1}{1 + z}}$

Where;

a₀ = The current size of the Universe

a = The size of the early Universe = 5% of a

Therefore;

$\displaystyle \frac{a}{a_0} =5\% = 0.05= \frac{1}{1 + z}$

$\displaystyle 0.05 = \frac{1}{1 + z}$

0.05 + 0.05·z = 1

$\displaystyle z = \mathbf{ \frac{1 - 0.05}{0.05} } = 19$

The redshift is of the observed light is, z = <u>19</u>

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4 0

2 years ago

A small object begins a free-fall from a height of =81.5 m at 0=0 s . After τ=2.20 s , a second small object is launched vertica

-BARSIC- [3]

Answer:

33.2 m

Explanation:

For the first object:

y₀ = 81.5 m

v₀ = 0 m/s

a = -9.8 m/s²

t₀ = 0 s

y = y₀ + v₀ t + ½ at²

y = 81.5 − 4.9t²

For the second object:

y₀ = 0 m

v₀ = 40.0 m/s

a = -9.8 m/s²

t₀ = 2.20 s

y = y₀ + v₀ t + ½ at²

y = 40(t−2.2) − 4.9(t−2.2)²

When they meet:

81.5 − 4.9t² = 40(t−2.2) − 4.9(t−2.2)²

81.5 − 4.9t² = 40t − 88 − 4.9 (t² − 4.4t + 4.84)

81.5 − 4.9t² = 40t − 88 − 4.9t² + 21.56t − 23.716

81.5 = 61.56t − 111.716

193.216 = 61.56t

t = 3.139

The position at that time is:

y = 81.5 − 4.9(3.139)²

y = 33.2

7 0

3 years ago

If the Sun suddenly went dark, we would not know it until its light stopped arriving on Earth. How long would that be, in second

Gre4nikov [31]

Answer: 500 s

Explanation:

Speed $v$ is defined as a relation between the distance $d$ and time $t$ :

$v=\frac{d}{t}$

Where:

$v=3(10)^{8}m/s$ is the speed of light in vacuum

$d=1.5(10)^{11}m$ is the distance between the Earth and Sun

$t$ is the time it takes to the light to travel the distance $d$

Isolating $t$ :

$t=\frac{d}{v}$

$t=\frac{1.5(10)^{11}m}{3(10)^{8}m/s}$

Finally:

$t=500 s$

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2 years ago

Which type of map would you most likely use to locate mineral deposits? A. topographic B. geologic C. satellite D. hazard

qwelly [4]

I think you would be using a topographic Map, So the answer should be A

3 0

2 years ago

A man stands at the midpoint between two speakers that are broadcasting an amplified static hiss uniformly in all directions. Th

Illusion [34]

Answer:

Explanation:

The power of each of the speakers is 0.535 W. At a distance d intensity of sound can be found by the following formula

Intensity of sound = Power / 4π d²

= .535 / 4 x 3.14 x (27.3/2)²

= 2.286 x 10⁻⁴ J m⁻² s⁻¹

Intensity of sound due to other source = 5.715 x 10⁻⁵J m⁻² s⁻¹

Total intensity = 2 x 2.286 x 10⁻⁴J m⁻² s⁻¹

= 4.57 x 10⁻⁴J m⁻² s⁻¹

b ) In this case, man is standing at distances 18.15 m and 9.15 m from the sources .

The total intensity of sound reaching him is as follows

0.535 / (4 π x18.15² ) + 0.535 / (4 π x9.15² )

= 1.293 x 10⁻⁴ + 5.087 x 10⁻⁴

= 6.38 x 10⁻⁴J m⁻² s⁻¹

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2 years ago