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Step2247 [10]
3 years ago
9

Technology is the tool, but without proper IG policies and a culture of compliance that supports the knowledge workers following

IG policies, any effort to secure confidential information assets will fail. Why is that? With an old IT adage in mind, even a perfect IT program ………………………...?
Computers and Technology
1 answer:
creativ13 [48]3 years ago
5 0

Answer:

Option B Is correct. It will fail without user commitment.

Explanation:

In the modern world, technology occupies an essential place. The technological tools in the industry today facilitate and expedite a huge amount of tasks, allowing automated work, mass production, software analysis, quality control, among others.

However, these tools can only work effectively when they are under the observation and supervision of trained human personnel, otherwise, a program designed to make 3D prints can fail, and without anyone to take action, it will cause a great waste of material, time and money.

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Write a function called factor that determines for a pair of integers whether the second integer is a factor of the first. The f
Aleks04 [339]
<h2>Answer:</h2>

//import the Scanner class to allow for user's input

import java.util.Scanner;

//Declare the class and call it FactorClass

public class FactorClass {

   

   //Declare the function factor

   //It returns either true or false, therefore the return type is boolean

   //It receives two arguments - a and b

   public static boolean factor(int a, int b){

       

       //Check if a is divisible by b.

       //Return true if yes

       if(a % b == 0){

           return true;

       }

       

       //return false if a is not divisible by b

       return false;

   

   }  // End of method factor

   

   

   //The main method to test the function factor()

   public static void main(String[] args) {

       

       //Create an object of the Scanner class

       Scanner input = new Scanner(System.in);

       

       //Prompt the user to enter the pair of numbers

       System.out.println("Enter the pair of numbers (separated by a space)");

       

       //grab and store the first number in a variable

       int firstnum = input.nextInt();

       

       //grab and store the second number in another variable

       int secondnum = input.nextInt();

       

       

       //With the variables, call the factor() method

       //If it returns true, print the adequate message

       if(factor(firstnum, secondnum)){

           System.out.println(secondnum + " is a factor of " + firstnum);

       }

       

       //If it returns false, print the adequate message

       else{

           System.out.println(secondnum + " is NOT a factor of " + firstnum);

       }

   

 }            // End of main method

   

}    // End of class declaration

==============================================================

<h2>Sample Output 1:</h2>

>> Enter the pair of numbers  separated by a space

8 4

>> 4 is a factor of 8

==============================================================

<h2>Sample Output 2:</h2>

>> Enter the pair of numbers  separated by a space

9 4

>> 4 is NOT a factor of 9

==============================================================

<h2>Explanation:</h2>

The above code has been written in Java and it contains comments explaining every segment of the code. Kindly go through the comments for better understanding of the code.

For simplicity, the code is re-written as follows with little or no comments;

import java.util.Scanner;

//Declare the class and call it FactorClass

public class FactorClass {

   

   public static boolean factor(int a, int b) {

       if(a % b == 0){

           return true;

       }

       

       //return false if a is not divisible by b

       return false;

   

   }  // End of method factor

   

   

   //The main method to test the function factor()

   public static void main(String[] args) {

       

       //Create an object of the Scanner class

       Scanner input = new Scanner(System.in);

       

       //Prompt the user to enter the pair of numbers

       System.out.println("Enter the pair of numbers (separated by a space)");

       

       //grab and store the first number in a variable

       int firstnum = input.nextInt();

       

       //grab and store the second number in another variable

       int secondnum = input.nextInt();

       

       

       if(factor(firstnum, secondnum)){

           System.out.println(secondnum + " is a factor of " + firstnum);

       }

       

       else{

           System.out.println(secondnum + " is NOT a factor of " + firstnum);

       }

    }

   

}

3 0
3 years ago
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