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Lana71 [14]
3 years ago
8

Describe the scope of the variables in this code.

Computers and Technology
2 answers:
Solnce55 [7]3 years ago
7 0

Answer:

The scope of petName is local to the class pet.

The scope of color is accessible by all parts of the program.

Explanation:

The variable petName is local to the class, because the variable was created in a function whose name begins with two underscores.

The variable color, while created in the petCarrier class, is accessible to the entire function. It was not created in a function whose name begins with an underscore.

Correct answer edge 2020

tensa zangetsu [6.8K]3 years ago
6 0

Answer:

Scope of petName is only limited to class pet (pet class) and scope of color is accessible to the entire program.

Explanation:

petName is restricted by the contructor with an underscore: def __init__(self,strSpecies,strName):, meaning it cannot be manipulated outside that class and color does not have that.

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You may save more money by using a a0 service, but you will spend more time on creating a contract.
Anon25 [30]

Answer:

contractor management outsourcing

Explanation:

For any recruiter, two things are important. They want to ensure more time, and hence more money. By the time I mean, they want to avoid investing time in something that does not generate revenues. And unfortunately, there exists a bundle of such irrelevant, and yet must-do activities which we need to perform. However, if we opt for contractor management outsourcing to a better management employment relationship, we save a lot of time and earn more as a recruiter. However, we then spend more time creating a contract, as even a single faulty clause can be hard for you to engulf in the future. And that is why it requires more time. However, the good part is, we as a recruiter are happy by the end of the day, as we earn more profit. And it's due to better resource and time management.

3 0
3 years ago
4.5 Code Practice
Alex787 [66]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

This program is written in C++.

                                                                         

#include <iostream>

using namespace std;

int main()

{

   

   string word;// variable for taking user input

   int cond;// to set condition true if user preses the stop and exit from loop

   

   cout<<"Enter word: \n";

   cin>>word;

   do// start while loop

   {

       

       

       if(word=="stop" || word =="STOP" || word == "Stop")// if user enter word stop, then program exit

       {

       cond=0;

       

       }

       else//otherwise loop continue

       {

           cout<<" You Entered "+ word +"\n";

           cout<<"Enter word: \n";

           cin>>word;

           cond=1;

       }

   }  

   while(cond == 1);// if user don't enter word "stop" loop run continuesly.  

   cout<<"Program exit";

   

   return 0;

}

5 0
3 years ago
Write a method transpose, that takes as argument a 2D array of integers, myTable, and returns the transpose of myTable. The tran
Gelneren [198K]

Answer:

The program to this question can be given as:

Program:

import java.util.*; //import package

public class Main //defining class

{

public static int[][] transpose(int[][] a1) //defining function transpose

{

int i,j; //define variables

int[][] transpose = new int[a1[0].length][a1.length]; //define variable transpose.

//loop for transpose matrix.

for(i = 0; i < a1.length; i++)  

{

for(j = 0; j < a1[i].length; j++)

{

transpose [j][i] = a1[i][j]; //hold value in transpose variable

}

}

return transpose ; //return transpose matrix.  

}

public static void main(String[] args) //main method.

{

int row,col,i,j; //defining variable.

Scanner obj = new Scanner(System.in); //creating Scanner class Object

System.out.print("Enter number of rows: ");//message

row = obj.nextInt(); //input rows form user.

System.out.print("Enter number of columns: ");//message

col = obj.nextInt(); //input columns form user.

int[][] a1 = new int[row][col]; //defining array.

System.out.println("Enter matrix"); //message

// loop for input array elements from user

for(i=0; i<a1.length;i++)  

{

for(j=0; j<a1[i].length;j++)  

{

a1[i][j]=obj.nextInt(); //input in array variable.

}

}

System.out.println("Matrix you insert :"); //message

// loop for display array.

for(i=0; i<a1.length;i++)  

{

for(j=0; j<a1[i].length;j++)  

{

System.out.print(a1[i][j]+" "); //print matrix

}

System.out.print("\n");

}

int[][] result = transpose(a1); //define result array variable that holds function value.

System.out.println("Transposed matrix is :");

//use loop for print Transpose matrix.

for(i = 0;i < result.length;i++)

{

for (j = 0; j < result[i].length;j++)

{

System.out.print(result[i][j] + " "); //print matrix

}

System.out.print("\n");

}

}

}

Output:

Enter number of rows: 2

Enter number of columns: 3

Enter matrix

2

3

4

9

8

7

Matrix you insert :

2 3 4  

9 8 7  

Transposed matrix is :

2 9  

3 8  

4 7  

Explanation:

The description of the above program can be given as:

  • In the above program firstly import a package, then declare a class that is "Main" inside a class defining a transpose() function this function returns a matrix in transpose form.
  • In the main class, we define a variable and matrix that is "row, col, i, j and a1[][]".  Then we Creating a scanner class object, which is used by row, col and a1[][] variables for user input.  
  • The row and col variables are used to declare matrix size and i, j variable is used in the loop for insert and display matrix.  
  • a1[][] matrix is used for input matrix elements and passes into transpose() function as an argument that returns a value that is held in the result variable. This is used as a loop for the print transpose matrix.

5 0
3 years ago
What is the internet?
aliya0001 [1]
What you're currently on. or a global computer network providing a variety of information and communication facilities, consisting of interconnected networks using standardized communication protocols.
7 0
3 years ago
Read 2 more answers
true or false: if a comment is posted anonymously, it cannot be considered hate speech or cyber bullying
pickupchik [31]

Answer:

false

Explanation:

Think about it

5 0
3 years ago
Read 2 more answers
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