4y-8=79+y
4y - y = 79 + 8
3y = 87
y = 87/3
y =29
answer: y = 29
Answer:
![\huge\purple{ x^2 +(y+2)^2 = 4}](https://tex.z-dn.net/?f=%5Chuge%5Cpurple%7B%20x%5E2%20%2B%28y%2B2%29%5E2%20%3D%204%7D)
Step-by-step explanation:
Circle is centred at (0, -2)
-> h = 0 & k = - 2
radius of the circle (r) = y-coordinate of the center = - 2
Equation of circle in standard form is given as:
![(x-h)^2 +(y-k)^2 = r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%20%2B%28y-k%29%5E2%20%3D%20r%5E2)
Plugging the values of h, k and r in the above equation, we find:
![(x-0)^2 +[y-(-2)]^2 = (-2)^2](https://tex.z-dn.net/?f=%28x-0%29%5E2%20%2B%5By-%28-2%29%5D%5E2%20%3D%20%28-2%29%5E2)
![\implies\huge\orange{ x^2 +(y+2)^2 = 4}](https://tex.z-dn.net/?f=%5Cimplies%5Chuge%5Corange%7B%20x%5E2%20%2B%28y%2B2%29%5E2%20%3D%204%7D)
This is the required equation of circle.
Let us assume the two unknown numbers to be "x" and "y".
Then
x + y = 37
And
xy = - 210
x = - 210/y
Now let us put the value of "x" in the first equation, we get
x + y = 37
- (210/y) + y = 37
y^2 - 210 = 37y
y^2 - 37y - 210 = 0
y^2 - 42y + 5y - 210 = 0
y(y - 42) + 5(y - 42) = 0
(y - 42)(y + 5) = 0
So when
y - 42 = 0
y = 42
Then
x = -(210/42)
= - 5
Again when
y + 5 = 0
y = -5
Then
x = 42
So the two unknown numbers are 42 and -5. I hope the procedure is clear enough for you to understand.
Answer:
hold on let me see
Step-by-step explanation: