Solve please I do not understand at all and please show work!

Mathematics

1 answer:

lina2011 [118]3 years ago

8 0

So the recipe calls for 96 grams of sugar, and one cup is 128 grams of sugar.

She added a half of a cup, and as they said before one cup was 128 grams of sugar. So half of 128 is 64. So she added 64 grams of sugar. The recipe needs 96 grams so 64 grams is not enough sugar.

So 96 grams minus 64 equals 32 grams. So she still needs 32 grams of sugar.

So since the answers are all in cups, we must convert our answer from grams to cups.

So we have 32 grams of sugar left and to convert it we must put the 32 grams out of one cup. Once again one cup is 128 grams of sugar. So the amount of cups we need is 32/128 (fraction).

Also we need to simplify our fraction to completely answer the question. So we divide the numerator and denominator by 32.

So the final answer is 1/4. So the answer is D or the last answer out of the multiple choice.

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The prices of all college textbooks follow a bell-shaped distribution with a mean of $113 and a standard deviation of $12. Using

Soloha48 [4]

Step-by-step explanation:

In statistics, the empirical rule states that for a normally distributed random variable,

68.27% of the data lies within one standard deviation of the mean.

95.45% of the data lies within two standard deviations of the mean.

99.73% of the data lies within three standard deviations of the mean.

In mathematical notation, as shown in the figure below (for a standard normal distribution), the empirical rule is described as

$\Phi(\mu \ - \ \sigma \ \leq X \ \leq \mu \ + \ \sigma) \ = \ 0.6827 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi(\mu \ - \ 2\sigma \ \leq X \ \leq \mu \ + \ 2\sigma) \ = \ 0.9545 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi}(\mu \ - \ 3\sigma \ \leq X \ \leq \mu \ + \ 3\sigma) \ = \ 0.9973 \qquad (4 \ \text{s.f.})$

where the symbol $\Phi$ (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, $\mu$ is the mean and $\sigma$ is the standard deviation of the normal distribution defined as $N(\mu, \ \sigma)$ .

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution $N(113, \ 12)$ ,

$\Phi(113 \ - \ 3 \ \times \ 12 \ \leq \ X \ \leq \ 113 \ + \ 3 \ \times \ 12) \ = \ 0.9973 \\ \\ \\ \-\hspace{1.75cm} \Phi(113 \ - \ 36 \ \leq \ X \ \leq \ 113 \ + \ 36) \ = \ 0.9973 \\ \\ \\ \-\hspace{3.95cm} \Phi(77 \ \leq \ X \ \leq \ 149) \ = \ 0.9973$