Answer:
w^2*(w+4)*(w^2+10)
Step-by-step explanation:
w^5+4w^4+10w^3+40w^2
w^2*(w^3+4w^2+10w+40)\w^2*(w^2*(w+4)+10(w+4))
w^2*(w+4)*(w^2+10)
Answer:
See explanation below
Step-by-step explanation:
Since each time after the person gets off the scale, the reading is 2 lb the person's weight must be near the mean of
148-2, 151-2, 150-2, 152-2; that is to say, near the mean of 146, 149, 148, 150 = (146+149+148+150)/4 = 148.25
We could estimate the uncertainty as <em>the standard error SE
</em>
where
<em>s = standard deviation of the sample
</em>
<em>n = 4 sample size.
</em>
Computing s:
So, the uncertainty is 1.479/2 = 0.736
<em>It is not possible to estimate the bias, since it is the difference between the true weight and the mean, but we do not know the true weight.
</em>
So, 4/3 - 2i
4/3 - 2i = 12/13 + i8/13
multiply by the conjugate:
3 + 2i/3 + 2i
= 4(3 + 2i)/(3 - 2i) (3 + 2i)
(3 - 2i) (3 + 2i) = 13
(3 - 2i) (3 + 2i)
apply complex arithmetic rule: (a + bi) (a - bi) = a^2 + b^2
a = 3, b = - 2
= 3^2 + (- 2)^2
refine: = 13
= 4(3 + 2i)/13
distribute parentheses:
a(b + c) = ab + ac
a = 4, b = 3, c = 2i
= 4(3) + 4(2i)
Simplify:
4(3) + 4(2i)
12 + 8i
4(3) + 4(2i)
Multiply the numbers: 4(3) = 12
= 12 + 2(4i)
Multiply the numbers: 4(2) = 8
= 12 + 8i
12 + 8i
= 12 + 8i/13
Group the real par, and the imaginary part of the complex numbers:
Your answer is: 12/13 + 8i/13
Hope that helps!!!
The answer will be around 145
Answer:
29
Step-by-step explanation: