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olga nikolaevna [1]
3 years ago
13

A student wants to do scientific research on how nuclear fusion can be used

Chemistry
1 answer:
Slav-nsk [51]3 years ago
7 0

Answer:

A physicist

Explanation:

A physicist is one who deals with matter energy and how they are related

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What is the effect of pressure on boiling point??? 1 mark answer plsss
d1i1m1o1n [39]

Answer:

direct effect

Increasing the pressure increases the boiling point and decreasing the pressure decreases the boiling point

8 0
3 years ago
Read 2 more answers
How many L of a 7.5 H2SO4 stock solution would you need to prepare a dilute solution 100 L of 0.25M H2SO4
blsea [12.9K]

Answer:

3.33 L

Explanation:

We can solve this problem by using the equation:

  • C₁V₁=C₂V₂

Where the subscript 1 refers to one solution and subscript 2 to the another solution, meaning that in this case:

  • C₁ = 0.25 M
  • V₁ = 100 L
  • C₂ = 7.5 M
  • V₂ = ?

We input the data:

  • 0.25 M * 100 L = 7.5 M * V₂
  • V₂ = 3.33 L

Thus the answer is 3.33 liters.

3 0
3 years ago
What is the atomic number of an atom that has 20 protons and 20 neutrons
vladimir2022 [97]

Answer:

20

Explanation:

Hi there!

We need to find the atomic number of an atom that has 20 protons and 20 neutrons

the atomic number of an atom is equivalent to the amount of protons an atom has, as the number of protons determines what element an atom is.

Since the atom has 20 protons, the atomic number of the said atom is <u>20</u>

Hope this helps!  

5 0
3 years ago
How to tell the formula for elements compounds and mixtures?
Kay [80]
Search it up on google
3 0
4 years ago
Un estudiante debe preparar una disolución 2M de NaCl (58,44 g/mol) en un recipiente de 7L. ?Cuántos gramos de NaCl debe agregar
Gnesinka [82]

Answer:

818.2 g.

Explanation:

  • Molarity is the no. of moles of solute per 1.0 L of the solution.

<em>M = (no. of moles of NaCl)/(Volume of the solution (L))</em>

<em></em>

M = 2.0 M.

no. of moles of NaCl = ??? mol,

Volume of the solution = 7.0 L.

∴ (2.0 M) = (no. of moles of NaCl)/(7.0 L)

∴ (no. of moles of NaCl) = (2.0 M)*(7.0 L) = 14.0 mol.

  • To find the mass of NaCl, we can use the relation:

<em>no. of moles of NaCl = mass/molar mass</em>

<em></em>

<em>∴ mass of NaCl = (no. of moles of NaCl)*(molar mass) =</em> (14.0 mol)*(58.44 g/mol) = <em>818.2 g.</em>

3 0
3 years ago
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