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scZoUnD [109]
4 years ago
13

A squirrel running up a tree and sitting on a branch shows what kind of

Chemistry
2 answers:
Yanka [14]4 years ago
7 0

Answer:

d

Explanation:

its right to be sydinachiondical

blondinia [14]4 years ago
6 0

Answer:

D. Kinetic energy converting to gravitational potential energy.

<em>APEX</em>

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The average weather conditions of a region
Verdich [7]

Answer:

A) Climate

Hope this helps !

6 0
3 years ago
Which of the following would be found in both eukaryotic AND prokaryotic cells?
beks73 [17]
Nucleus ,endoplasmic reticulum
7 0
3 years ago
Read 2 more answers
How many grams of oxygen are required to burn 0.10mole of c3h8?
Anastaziya [24]
1mol—44g/mol
0.10mol—x
x=0.10*44
x=4.4 g
8 0
3 years ago
What would be the volume of 0.500 mole of an ideal gas at a temperature of 273.15 Kelvins and 1 atm?
uysha [10]

Answer:

V = 11.21 L

Explanation:

Given data:

Volume of helium = ?

Number of moles = 0.500 mol

Temperature = 273.15 K

Pressure of gas = 1 atm

Solution:

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

V = nRT/P

V = 0.500 mol ×  0.0821 atm.L/ mol.K  × 273.15 K / 1 atm

V = 11.21 L / 1

V = 11.21 L

8 0
3 years ago
2 NO + O22 NO2 is second order in NO and first order in O2. Complete the rate law for this reaction in the box below. Use the fo
riadik2000 [5.3K]

Answer : The value of rate of reaction is 1.35\times 10^{-8}Ms^{-1}

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given chemical equation is:

2NO+O_2\rightarrow 2NO_2

Rate law expression for the reaction is:

\text{Rate}=k[NO]^a[O_2]^b

As per question,

a = order with respect to NO  = 2

b = order with respect to O_2 = 1

Thus, the rate law becomes:

\text{Rate}=k[NO]^2[O_2]^1

Now, calculating the value of rate of reaction by using the rate law expression.

Given :

k = rate constant = 9.87\times 10^3M^{-2}s^{-1}

[NO] = concentration of NO = 7.86\times 10^{-3}M

[O_2] = concentration of O_2= 2.21\times 10^{-3}M

Now put all the given values in the above expression, we get:

\text{Rate}=(9.87\times 10^3M^{-2}s^{-1})\times (7.86\times 10^{-3}M)^2\times (2.21\times 10^{-3}M)^1

\text{Rate}=1.35\times 10^{-8}Ms^{-1}

Hence, the value of rate of reaction is 1.35\times 10^{-8}Ms^{-1}

7 0
3 years ago
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