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valentinak56 [21]
3 years ago
8

A land rover drops from rest a vertical distance of 1000 m to the surface of planet in 15 seconds what is the magnitude of the a

cceleration due to gravity on the planet
Physics
1 answer:
umka21 [38]3 years ago
6 0

Answer:

66.6 or it could be 66.66 one of those

Explanation:

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Question 6
Effectus [21]

Answer:

4.9 x 10-23 N

Explanation:

I took the test

3 0
3 years ago
A nonlinear spring is used to launch a toy car. The car is pushed against the spring, compressing the spring 2.5 cm. The force t
dybincka [34]

Answer:

1.56 J

Explanation:

given,

Spring compression, x = 2.5 cm

Force exerts by the spring,

F = - k x

k = 5000 N/m

Potential energy stored = ?

energy stored in the spring

PE = \dfrac{1}{2}kx^2

PE = \dfrac{1}{2}\times 5000\times 0.025^2

PE = 1.56 J

Hence, the potential energy stored in the car is equal to 1.56 J.

5 0
3 years ago
Graham and hunter are circus performers. a cable lifts graham into the air at a constant speed of 1.5 ft/s. when graham’s arms a
siniylev [52]

Answer:

The equations are :

h = 18 + 1.5t

h = 5 + 24t - 16t^2

Explanation:

Speed = distance/time

1.5ft/s = 18ft/t

1.5t=18

The equation to determine height h= 18 + 1.5t

Graham moved another 5ft further with a velocity of 24ft/s

The equation to determine his height will be:

h= 5 + 24t -16t^2

3 0
3 years ago
Read 2 more answers
A solid ball with a mass of 3.56 kg and a radius of 0.094 m starts from rest at the top of a 86.4 ⦠slope with a vertical heigh
PtichkaEL [24]
Let: m=1.50Kg, r=0.094m, h=2.50m, teta=86.4 and g=9.81m/s^2. The moment of inertia of a sphere is I=(2/5)*m*r^2, vi=0m/s, hf=0m, and the condition that a spherical object is rolling whitout slipping is w=V/r. So, by conservation of energy: mgh= (1/2)*((m*Vf^2)+(I*wf)). substituting, and clearing, Vf=((10/7)*g*h)^(1/2)=((10/7)*(9.81)*(2.50))^(1/2)=5.9190 m/s
8 0
3 years ago
A bicyclist and his bike together have a mass of 70 kg and a speed of 6 m/s. How much work would be done for the biker to accele
antoniya [11.8K]

Answer:

Correct answer:  W = 2,240 J

Explanation:

Given:

m = 70 kg

V₁ = 6 m/s

V₂ = 10 m/s

W = ?

Work is a measure of change in this case of kinetic energy:

W = ΔE = (m V₂²)/ 2 - (m V₁²)/ 2 = (m / 2) · (V₂² -  V₁²)

W = (70 / 2) ·  (10² - 6²) = 35 · (100 - 36) = 35 · 64 = 2,240 J

W = 2,240 J

God is with you!!!

3 0
3 years ago
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