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zmey [24]
3 years ago
8

A 5 kg block is being pulled to the right by a rope tied to it. the block is accelerating at 2 m/s2 to the right. how much force

is being applied? use the formula f= m x a
Physics
2 answers:
Feliz [49]3 years ago
8 0
10N
The formula is F=ma
Substitute 5kg for the mass and 2m/s^2 for acceleration
just olya [345]3 years ago
8 0
Here, We know, F = m * a
F = 2 * 5
F = 10 N

In short, Your Answer would be 10 N

Hope this helps!
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A truck is traveling at 2.0 m/s. It slows to a stop at a constant rate over 3.00 s. How far does the car travel during those 3.0
earnstyle [38]

Answer:

During those 3.00 seconds before stopping, the car travels a distance of 6 m.

Explanation:

The simple rule of three is a tool that is used to quickly solve problems, where three pieces of information must be known, and one of them operates as an unknown to be known.

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Being a, b and c known data and x the unknown, the value that we want to know, the rule of three when the magnitudes are directly proportional is applied as follows:

a ⇒ b

c ⇒ x

So: x=\frac{c*b}{a}

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8 0
3 years ago
PLSLPSLLPSLPSLPS HELP I ONLY HAVE 5 MINS PLEASE
UkoKoshka [18]

Answer:

0.19m/s²

Explanation:

Initial velocity(u) = 50×1000/60×60

=13.88 m/s

Final velocity(v) = 36.5×1000/60×60

=10.13 m/s

Acceleration(a) = v-u/t

=10.13-13.88/19.5

a= -0.19m/s²

-a = 0.19m/s²

The magnitude of retar dation is 0.19m/s²

5 0
2 years ago
Read 2 more answers
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