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Mrrafil [7]
3 years ago
9

A sample of oxygen occupies 560. ml when the pressure is 800.00 mm hg. at constant temperature, what volume does the gas occupy

when the pressure decreases to 700.0 mm hg?
Physics
1 answer:
raketka [301]3 years ago
7 0
Answer:
final volume = 640 ml

Explanation:
To answer this question, we will use Boyle's law which states that:
"At constant temperature, the product of the pressure and the volume of a given mass of gas will be constant"
Thereore:
P1V1 = P2V2
800*560 = 700*V2
V2 = 640 ml

Hope this helps :)
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Explanation:

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4 0
2 years ago
A number is written in scientific notation when it is the product of a number less than 10 but greater than or equal to 1 and a
Bess [88]

Answer:

Mass = 1.99 * 10^{30} kg

Explanation:

Given

Mass = 1,990,000,000,000,000,000,000,000,000,000\ kg

Required

Rewrite using scientific notation

The format of a number in scientific notation is

Digit = a * 10^n

Where 1 \geq\ a\geq\ 10

So the given parameter can be rewritten as

Mass = 1.99 * 1,000,000,000,000,000,000,000,000,000,000\ kg

Express as a power of 10

Mass = 1.99 * 10^{30} kg

Hence, the equivalent of the mass of the sun in scientific notation is:

Mass = 1.99 * 10^{30} kg

7 0
3 years ago
A satellite with a mass of 2,000 ㎏ is inserted into an orbit that is twice the Earth' s radius. W hat is the force of gravity on
dolphi86 [110]

Answer:

option (b) 4900 N

Explanation:

m = 2000 kg, R = 6380 km = 6380 x 10^3 m, Me = 5.98 x 10^24 kg, h = R

F = G Me x m / (R + h)^2

F = G Me x m / 2R^2

F = 6.67 x 10^-11 x 5.98 x 10^24 x 2000 / (2 x 6380 x 10^3)^2

F = 4900 N

4 0
3 years ago
A 50 kg pitcher throws a baseball with a mass of 0. 15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is
dsp73

The velocity of the pitcher at the given mass is 0.1 m/s.

The given parameters:

  • <em>Mass of the pitcher, m₁ = 50 kg</em>
  • <em>Mass of the baseball, m₂ = 0.15 kg</em>
  • <em>Velocity of the ball, u₂ = 35 m/s</em>

<em />

Let the velocity of the pitcher = u₁

Apply the principle of conservation of linear momentum to determine the velocity of the pitcher as shown below;

m₁u₁ = m₂u₂

u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{0.15 \times 35}{50} \\\\u_1 = 0.105 \ m/s\\\\u_1 \approx 0.1 \ m/s

Thus, the velocity of the pitcher at the given mass is 0.1 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/13589460

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