In an atom of hydrogen the orbit radius is given by the formula:
r = n² · α₀
where:
n = number of orbit = 15
α₀ = Bohr radius (innermost radius) = 0.529 Â
Since d = 2 · r, we can write:
d = n² · d₀
= 15² · 1.06
= 238.5 Â
Hence, the <span>diameter of the fifteenth orbit of the hydrogen atom is 238.5 </span>Â.
Answer:
The correct option is;
C. Electrons can act as both waves and particles
Explanation:
The quantum theory theory developed by Max Planck established that effect of radiation on a blackbody can be explained by the fact that energy can exhibit physical characteristics which implies that energy can have both wave-like and physical characteristics
With Planck's law, light and electrons are known as having wave particle duality, that is they can act as both waves and particles.
Answer:
d = 0.294 m
1) g = k*d/m
To find k: k = 4π²*m/T²
T = 16.3/11 = 1.4818 sec
So
k = 4.495 N/m
Using (1),
g = 4.495*0.294/0.25 = 5.286 m/s²
Explanation:
Use the equation PV=nRT to find no. of moles (n)
For this;
At STP
Pressure= P= 1 atm
Temperature=T = 273.16 K
Volume= V= 16.3 L = 16.3 dm³
R = 0.0821 dm³ atm K⁻¹ mol⁻¹
Now,
PV= nRT
(1)(16.3)=n(0.0821)(273.16)
n = 0.727 mol
Now, again using the same equation for
Pressure=P= 735 torr
Temperature=T= 57°C
T= 57+273 =330 K
n= 0.727 mol (form previous calculation)
R= 62.4 dm³ torr K⁻¹ mol⁻¹
Now,
PV= nRT
(735)V= (0.727)(62.4)(330)
V= 20.37 dm³