All categories

4 years ago

A water tank was 1/8 full of water

Mathematics

2 answers:

vekshin14 years ago

8 0

Answer:

16,800 Liters

Step-by-step explanation:

Convert 3/4 into eighths, because it was already 1/8 full before the 10,500 liters were added:

3/4= 6/8

Subtract 1/8 from that (because it was already 1/8 full):

6/8-1/8= 5/8

Divide 10,500 by the 5 (because you want how many liters each part is):

10,500/5= 2,100

You know can say that every eighth is 2,100 Liters of water.

Multiply that by the 8 total parts it can hold:

2,100x8= 16,800 Liters

Molodets [167]4 years ago

8 0

Answer:

16800

Step-by-step explanation:

1/8 ÷ 3/4 × 10500/1

1/8 × 4/3 × 10500/1

1/5× 10500/1

= 2100× 8

= 16800

You might be interested in

Find the coordinates of S after a rotation of the triangle 90 degrees counterclockwise about the origin

Neko [114]

We first start by finding the actual coordinates of the pre - image's point S.

Assuming the x and y axis count by 1s, as there is no labels, we can conclude that:

The point's x coordiate is 4 to the left from the origin, or -4.

The point's y coordinate is 4 up from the origin, or 4.

So, the coordinates of Point S is (-4, 4).

Next, we apply the translation rule for a 90 degree counterclockwise rotation to the point's coordinates. The rule is (x, y) --> (-y, x). Using this rule on our coordinates, we get:

(-4, 4) --> (-4, -4)

So, the new coordinates of point S prime after a 90 degree counterclockwise rotation are (-4, -4).

4 0

3 years ago

Which angle is complementary to DFE? Pls answer

zaharov [31]

Answer:

<DFA

Step-by-step explanation:

When combined (<DFA and <DFE), they'll form 90 degrees which will make them complementary

6 0

3 years ago

Read 2 more answers

5.5 x 10^-8 in standard form

dangina [55]

Step-by-step explanation:

0.000000055

hope it helps you

3 0

3 years ago

PLEASE SHOW ALL THE STEPS THAT YOU USE TO SOLVE THIS PROBLEM

Mademuasel [1]

Answer:

{x = 1 , y=1, z=0

Step-by-step explanation:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

{-2 x - y + z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2: