All categories

3 years ago

What is the kinetic energy of a cat running 5 m/s

Physics

1 answer:

dusya [7]3 years ago

4 0

The cat's kinetic energy is

(1/2) x (the cat's mass in kg) x (25 m²/sec²).

The unit is [joules] .

You might be interested in

The speed of a bus increases uniformly from 15meter per seconds to 60 meter per seconds in 20second.Calculate, the acceleration.

Anarel [89]

Answer:

2.25 m/s²

Explanation:

Acceleration = change in velocity / time taken

= (60-15)/20

= 2.25 m/s²

6 0

4 years ago

Decreasing a telescope's eyepiece focal length will _____.

Novay_Z [31]

I believe the correct answer from the choices listed above is the first option. Decreasing a telescope's eyepiece focal length will increase magnification. The magnification of the telescope image is (focal length of the objective) divided by (focal length of the eyepiece). Hope this answers the question.

7 0

3 years ago

Read 2 more answers

A car traveling in a straight line has a velocity of 5.0 m/s. After an acceleration of 0.75 m/s/s, the cars velocity is 8.0. In

Bogdan [553]

Vs - velocity on beginning
ve - velocity on ending. You've got:
$v_s = 5 \frac{m}{s} \\ v_e=8 \frac{m}{s} \\ \hbox{Then:} \\ \Delta v=v_e - v_s = 8 \frac{m}{s} - 5\frac{m}{s}=3 \frac{m}{s} \\ a=0,75 \frac{m}{s^2} \\ \hbox{And from formula:} \\ a=\frac{\Delta v}{\Delta t} \qquad \Rightarrow \qquad \Delta t= \frac{\Delta v}{a} \\ \hbox{Substitute:} \\ \Delta t=\frac{3\frac{m}{s}}{0,75 \frac{m}{s^2}}= \frac{3}{\frac{3}{4}} s= 3 \cdot \frac{4}{3} s= 4 s$
So he needed 4 second.

3 0

3 years ago

The process of arriving at a general conclusion based on the observation of specific examples is called ___________ reasoning.

olga55 [171]

The process of arriving at a general conclusion based on the observation of specific examples is called inductive reasoning. It is a logical process where multiple premises are combined to obtain a conclusion. It is used in applications that involve prediction and forecasting.

7 0

3 years ago

A rocket with a mass of 62,000 kg (including fuel) is burning fuel at the rate of 150 kg/s and the speed of the exhaust gases is

mezya [45]

Answer:

h≅ 58 m

Explanation:

GIVEN:

mass of rocket M= 62,000 kg

fuel consumption rate = 150 kg/s

velocity of exhaust gases v= 6000 m/s

Now thrust = rate of fuel consumption×velocity of exhaust gases

=6000 × 150 = 900000 N

now to need calculate time t = amount of fuel consumed÷ rate

= 744/150= 4.96 sec

applying newton's law

M×a= thrust - Mg

62000 a=900000- 62000×9.8

acceleration a= 4.71 m/s^2

its height after 744 kg of its total fuel load has been consumed

$h= \frac{1}{2}at^2$

$h= \frac{1}{2}4.71\times4.96^2$

h= 58.012 m

h≅ 58 m

4 0

4 years ago