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3 years ago

Decreasing a telescope's eyepiece focal length will _____.

Physics

2 answers:

krek1111 [17]3 years ago

8 0

Answer:

increase magnification

Explanation:

Novay_Z [31]3 years ago

7 0

I believe the correct answer from the choices listed above is the first option. Decreasing a telescope's eyepiece focal length will increase magnification. The magnification of the telescope image is (focal length of the objective) divided by (focal length of the eyepiece). Hope this answers the question.

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(a) What is the tangential acceleration of a bug on the rim of a 13.0-in.-diameter disk if the disk accelerates uniformly from r

Oksi-84 [34.3K]

Answer:

0.321659377 m/s²

1.383138458 m/s

0.321659377 m/s²

0.62667 m/s²

0.7044 m/s² and 27.17°

Explanation:

d = Diameter of rim = 13 in = $13\times 0.0254=0.3302\ m$

r = Radius = $\frac{d}{2}=\frac{0.3302}{2}=0.1651\ m$

$\omega_f$ = Final angular velocity = $80\times\frac{2\pi}{60}=8.37758\ rad/s$

$\omega_i$ = Initial angular velocity = 0

$\alpha$ = Angular acceleration

t = Time taken = 4.3 s

Equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{8.37758-0}{4.3}\\\Rightarrow \alpha=1.94827\ rad/s^2$

Tangential acceleration is given by

$a_t=r\alpha\\\Rightarrow a_t=0.1651\times 1.94827\\\Rightarrow a_t=0.321659377\ m/s^2$

The tangential acceleration of the bug is 0.321659377 m/s²

Tangential velocity is given by

$v=r\omega\\\Rightarrow v=0.1651\times 8.37758\\\Rightarrow v=1.383138458\ m/s$

The tangential velocity of the bug is 1.383138458 m/s

The tangential acceleration is constant which is 0.321659377 m/s²

Centripetal acceleration is given by

$a_c=\frac{a_tt^2}{r}\\\Rightarrow a_c=\frac{0.321659377^2\times 1}{0.1651}\\\Rightarrow a_c=0.62667\ m/s^2$

The centripetal acceleration of the bug is 0.62667 m/s²

The resultant of the acceleration gives us total acceleration

$a=\sqrt{a_t^2+a_c^2}\\\Rightarrow a=\sqrt{0.321659377^2+0.62667^2}\\\Rightarrow a=0.7044\ m/s^2$

Direction is given by

$\theta=cos^{-1}\frac{a_c}{a}\\\Rightarrow \theta=cos^{-1}\frac{0.62667}{0.7044}\\\Rightarrow \theta=27.17^{\circ}$

The magnitude and direction of the acceleration is 0.7044 m/s² and 27.17°

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4 years ago

How many grams of co2 are in 3 moles of the compound

Ber [7]

Answer:132.0285

Explanation: Hope this helps!

7 0

3 years ago

Read 2 more answers

This is the 3rd time I reposted this question lol.

Mamont248 [21]

Answer:

Blood absorbs nutrients and the waste products of cells. It carries waste away from cells and pumps nutrients through the whole body.

Explanation:

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3 years ago

What is the best definition of muscular strength

BabaBlast [244]

Answer:

Muscular strength is defined as the maximum amount of force that a muscle can exert against some form of resistance in a single effort. ... In the gym, a single repetition at a given weight is an example of muscular strength.

Explanation:

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3 years ago

In one scene in the movie The Godfather II, a solid gold phone is passed around a large table for everyone to see. Suppose the v

dangina [55]

Volume of gold in the phone = 10 cm^3
= 0.00001 m^3 
Density of gold = 19300 kg/m^3
1 kg mass = 2.2 pounds
Mass of 10 cm^3 of gold = 0.00001 m^3 * (19300 kg/m^3)
= 0.193 kg
So
0.193 kg = 0.193 * 2.2 pounds
= 0.43 pounds
I think there is something wrong with the options given in the question.

7 0

4 years ago