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torisob [31]
3 years ago
6

Decreasing a telescope's eyepiece focal length will _____.

Physics
2 answers:
krek1111 [17]3 years ago
8 0

Answer:

increase magnification

Explanation:

Novay_Z [31]3 years ago
7 0
I believe the correct answer from the choices listed above is the first option. Decreasing a telescope's eyepiece focal length will increase magnification. <span>The magnification of the </span>telescope<span> image is (</span>focal length<span> of the objective) divided by (</span>focal length <span>of the </span>eyepiece<span>). Hope this answers the question.</span>
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An electron is traveling horizontally toward the north in a uniform magnetic field that is directed vertically downward. In what
Arte-miy333 [17]

Answer:

e) upwrad z axis

Explanation:

To know the direction of the force we use the right hand rule.

The thumb points in the direction of the velocity, the fingers extended in the direction of the magnetic field and the palm of the hand in the direction of the force, this is for a positive charge if the charge is negative the force is in the opposite direction of The palm of the hand.

 

Let's apply to our case.

The thumb is in the x direction, the fingers in the vertical direction and since the electron has a negative charge, the force is on the z axis (perpendicular to the blade, coming out)

In general, in the nomenclature of the cardinal points the positive x-axis is the East, the positive y-axis is the North. Therefore the answer must be up on the z axis

8 0
3 years ago
(ii) two locomotives approach each other on parallel tracks. each has a speed of 155 km/h with respect to the ground. if they ar
IgorLugansk [536]
You have to find an equation that would relate the two motions of the locomotives. When they meet at a certain point after being 8.5 km apart initially, then that means that their individual distances traveled is equal to 8.5 The solution is as follows:

Distance = speed*time
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t = 0.027 hour or 98.71 seconds
4 0
4 years ago
(1) Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy so
malfutka [58]

Solution :

The relationship between the strength of magnetic field and the radiusof a charged particle's path is obtained through Newton's second law, which is given by :

F = ma

F = qvB and $a=\frac{v^2}{r}$

Substituting these values in the second law of Newton,

$qvB=\frac{mv^2}{r}$

Now solving for B, we get:

$B = \frac{mv}{rq}$

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The field strength can be obtained by using the technology of today.

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3 years ago
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ziro4ka [17]

Energy is force * distance.

So force is energy/distance so 6000J/300m = 20N

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4 years ago
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Dafna1 [17]

Answer:

網站有中、英文版本,也有繁、簡體版,可通過每頁左上角的連結隨時網站有中、英文版本,也有繁、簡體版,可通過每頁左上角的連結隨時

Explanation:

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