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san4es73 [151]
2 years ago
13

What are two ways electromagnetic waves are used in a home computer scanner?

Physics
2 answers:
miss Akunina [59]2 years ago
8 0

Answer:

A and B

Explanation:

lilavasa [31]2 years ago
3 0

Answer:

A and B

Explanation:

A P E X , just took the quiz and got it right

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A porter can carry 40 bricks of 10 N load of each. He can carry up to 75m in 40 sec, calculate his power.​
alexira [117]

Answer:

750W

Explanation:

40×10= 400N

work done= force × distance

=400 × 75

=30000 J

Power= work done/ time

= 30000 ÷ 40

= 750 W

4 0
1 year ago
The blood pressure in the human body is greater at the feet than at the brain
GarryVolchara [31]
Blood pressure is greater in feet because of gravity
5 0
3 years ago
Read 2 more answers
Current is the movement of positive charges called electrons.
spayn [35]

Answer:

False -> negative charge

7 0
2 years ago
Read 2 more answers
A spherical asteroid of average density would have a mass of 8.7×1013kg if its radius were 2.0 km.A)If you and your spacesuit ha
WITCHER [35]

A) 0.189 N

The weight of the person on the asteroid is equal to the gravitational force exerted by the asteroid on the person, at a location on the surface of the asteroid:

F=\frac{GMm}{R^2}

where

G is the gravitational constant

8.7×10^13 kg is the mass of the asteroid

m = 130 kg is the mass of the man

R = 2.0 km = 2000 m is the radius of the asteroid

Substituting into the equation, we find

F=\frac{(6.67\cdot 10^{-11})(8.7\cdot 10^{13} kg)(130 kg)}{(2000 m)^2}0.189 N=

B) 2.41 m/s

In order to orbit just above the surface of the asteroid (r=R), the centripetal force that keeps the astronaut in orbit must be equal to the gravitational force acting on the astronaut:

\frac{GMm}{R^2}=\frac{mv^2}{R}

where

v is the speed of the astronaut

Solving the formula for v, we find the minimum speed at which the astronaut should launch himself and then orbit the asteroid just above the surface:

v=\sqrt{\frac{2GM}{R}}=\sqrt{\frac{2(6.67\cdot 10^{-11})(8.7\cdot 10^{13} kg)}{2000 m}}=2.41 m/s

3 0
3 years ago
How would I find the average distance for this?
Maslowich

Answer:

Explanation:add them then divide them by 100 I think

3 0
2 years ago
Read 2 more answers
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