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ser-zykov [4K]
3 years ago
12

The quotient of 7 and the sum of x and 1

Mathematics
1 answer:
Len [333]3 years ago
5 0

Answer:

7÷(x+1)

Step-by-step explanation:

7÷(x+1)

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What is the probability that this spinner will stop on blue or white when it is spun?
Eddi Din [679]

Answer:

1/2 or 50-50

Step-by-step explanation:

1/4 +1/4 = 1/2 or 50-50

8 0
3 years ago
Find the holes<br> <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7Bx%2B3%7D%7B%28x%2B1%29%28x-2%29%7D" id="TexFormula1" t
olga55 [171]

Answer:

<h2>           x=-1 and x=2</h2>

Step-by-step explanation:

The "holes" are the x-es where function doesn't exist.

one must not divide by 0, so given function doesn't exis if the denominator is equal 0

The product {(x+1)×(x-2)} is equal 0 if any of factors  {(x+1),(x-2)} is 0, so

x + 1 = 0    or    x - 2 = 0

x = - 1      or    x = 2

8 0
2 years ago
Instructions: Select the correct answer from the drop-down menu.
True [87]
Remember
(x^m)/(x^n)=x^(m-n)

7^16/6^12=7^(16-12)=6=7^4

so

7^4=7^-18/?
?=7^?

7^4=7^-18/7^?
7^-18/7^?=7^(-18-?)=7^4
-18-?=4
add 18
-?=22
tmes -1
?=-22
7^-22

answer is C
3 0
3 years ago
Read 2 more answers
a euro is equal to 1.2 American dollars. write an expression which estimates the number of dollars in x euros. Then estimate the
s2008m [1.1K]
1.2x

25=1.2x

1.2 ÷ 25 = x

x=20.83
5 0
3 years ago
Solve the equation for x∈Z <br><br>-x² +8x -14 ≥ 0
kenny6666 [7]
ax^2+bx+c=0\\\Delta=b^2-4ac\\if\ \Delta < 0\ then\ no\ solutions\\if\ \Delta=0\ then\ one\ solution:x=\frac{-b}{2a}\\if\ \Delta > 0\ then\ two\ solutions:x=\frac{-b\pm\sqrt\Delta}{2a}\\================================\\\\-x^2+8x-14\geq0\ \ \ \ |multiply\ both\ sides\ by\ (-1)\ \{change\ \geq\ on\ \leq\}\\\\x^2-8x+14\leq0\\\\a=1;\ b=-8;\ c=14\\\\\Delta=(-8)^2-4\cdot1\cdot14=64-56=8 > 0\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=\sqrt4\cdot\sqrt2=2\sqrt2

x_1=\frac{-(-8)-2\sqrt2}{2\cdot1}=\frac{8-2\sqrt2}{2}=\frac{8}{2}-\frac{2\sqrt2}{2}=\boxed{4-\sqrt2}\\\\x_2=\frac{-(-8)+2\sqrt2}{2\cdot1}=\frac{8+2\sqrt2}{2}=\frac{8}{2}+\frac{2\sqrt2}{2}=\boxed{4+\sqrt2}\\\\============================

ax^2+bx+c=0\\\\if\ a > 0\ then\ the\ parabola\ o pen\ up\\if\ a < 0\ then\ the\ parabola\ o pen\ down\\========================\\\\a=1 > 0-therefore\ o pen\ up\ (look\ at\ the\ picture)\\\\===============================\\\\Answer:x\in\left


Solutions\ in\ \mathbb{Z}:\\\\\sqrt2\approx1.4\\\\threfore:4-\sqrt2\approx4-1.4=2.6\ and\ 4+\sqrt2\approx4+1.4=5.4\\\\look\ at\ the\ second\ picture:x=3\ or\ x=4\ or\ x=5\ (x\in\{3;\ 4;\ 5\})

6 0
3 years ago
Read 2 more answers
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