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scoundrel [369]
3 years ago
8

You are taking a picture of a giraffe that is standing far away from you. The image is just too small, so you swap the 60-mm-foc

al-length lens in your camera for a 960 mm telephoto lens. By what factor does this increase the size of the image?
Physics
1 answer:
vfiekz [6]3 years ago
4 0

Explanation:

Given that, you are taking a picture of a giraffe that is standing far away from you. The image is just too small, so you swap the 60-mm-focal-length lens in your camera for a 960 mm telephoto lens such that,

m_1=960\ mm

m_2=60\ mm

We need to find the the factor with which the size of the image increases. It can be calculated by taking ratios of both m_1\ and\ m_2

So, \dfrac{m_1}{m_2}=\dfrac{960}{60}

\dfrac{m_1}{m_2}=16

So, the size of image increases by a factor of 16. Hence, this is the required solution.

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Fiber optic (FO) cables are based upon the concept of total internal reflection (TIR), which is achieved when the FO core and cl
kozerog [31]

Answer:

False

Explanation:

Though fiber active cable is based on the concept of internal reflection but it is achieved by refractive index which transmit data through fast traveling pulses of light. It has a layer of glass and insulating casing called “cladding,”and this is is wrapped around the central fiber thereby causing light to continuously bounce back from the walls of the Cable.

7 0
3 years ago
Satellite A is orbiting Earth at an altitude of 500 km and Satellite B is orbiting 800 km above the surface . How does the veloc
sp2606 [1]

The velocity of Satellite A is 2% greater than velocity of satellite B.

The given parameters;

  • <em>Altitude of Satellite A = 500 km</em>
  • <em>Altitude of Satellite B = 800 km</em>

The forces acting on the Satellites are given as follows;

F_c = \frac{mv^2}{r} \\\\F_g = \frac{GMm}{r^2} \\\\\frac{v^2}{r}  = \frac{GM}{r^2}\\\\v^2 = \frac{GM}{r} \\\\v^2 r = GM\\\\v_1^2 r _1 = v_2^2 r_2\\\\v_A^2r_A = v_B^2 r_B\\\\(\frac{v_A}{v_B} )^2 = \frac{r_B}{r_A} \\\\\frac{v_A}{v_B}  = \sqrt{\frac{r_B}{r_A} } \\\\\frac{v_A}{v_B}  = \sqrt{\frac{(800,000\  + \ 6.4 \times 10^6}{(500,000\  + \ 6.4 \times 10^6} )} \\\\\frac{v_A}{v_B}  =  1.02 \\\\v_A = 1.02 \ v_B

v_A = v_B( 100\% \ + 2\%)\\\\v_A = 100\%v_B \ + \ \ 2\% v_B\\\\v_A = v_B \ \ + \ 2\% v_B

Thus, the velocity of Satellite A is 2% greater than velocity of satellite B.

Learn more about velocity of satellite here: brainly.com/question/13981089

4 0
3 years ago
The diagrams show vectors. Which diagram represents the vector addition C = A
rewona [7]

Answer:

C

Explanation:

good luck :3

8 0
4 years ago
In which of these samples do the molecules mist likely have the least kinetic energy
KiRa [710]
Provide the examples again, no samples are presents.
8 0
3 years ago
A motorboat traveling on a straight course slows
never [62]

Answer:

2.572 m/s²

Explanation:

Convert the given initial velocity and final velocity rates to m/s:

  • 65 km/h → 18.0556 m/s
  • 35 km/h → 9.72222 m/s

The motorboat's displacement is 45 m during this time.

We are trying to find the acceleration of the boat.

We have the variables v₀, v, a, and Δx. Find the constant acceleration equation that contains all four of these variables.

  • v² = v₀² + 2aΔx

Substitute the known values into the equation.

  • (9.72222)² = (18.0556)² + 2a(45)
  • 94.52156173 = 326.0046914 + 90a
  • -231.4831296 = 90a
  • a = -2.572

The magnitude of the boat's acceleration is |-2.572| = 2.572 m/s².

3 0
3 years ago
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