An unknown element shiny in color, malleable, conducts electricity, and is in group 2 on the periodic table is a non-metal.

Two waves can share the same space and pass through one another. What type of interference occurs when the crests of one wave ov

bulgar [2K]

Question 25 Answer: Destructive interference occurs.

Question 26Answer: The waves are closer together (as they move) because the object is moving toward you.

4 0

2 years ago

Is it accurate to describe the physical universe as composed of only matter and energy?

Dennis_Churaev [7]

Yes, it is accurate to describe the physical universe as composed of only matter and energy. Some people might argue about the dark matter, but it is not yet defined properly. Different universes can be made up of different compositions but it is a fact that our universe is made of matter and energy.

7 0

3 years ago

Read 2 more answers

Estimate the wavelength corresponding to maximum emission from each of the following surfaces: the sun, a tungsten filament at 2

igomit [66]

Answer

Applying Wein's displacement

$\lamda_{max}\ T = 2898 \mu_mK$

1) for sun T = 5800 K

$\lambda_{max} = \dfrac{2898}{5800}$

$\lambda_{max} = 0.5 \mu_m$

2) for tungsten T = 2500 K

$\lambda_{max} = \dfrac{2898}{2500}$

$\lambda_{max} = 1.16 \mu_m$

3) for heated metal T = 1500 K

$\lambda_{max} = \dfrac{2898}{1500}$

$\lambda_{max} = 1.93 \mu_m$

4) for human skin T = 305 K

$\lambda_{max} = \dfrac{2898}{305}$

$\lambda_{max} = 9.50 \mu_m$

5) for cryogenically cooled metal T = 60 K

$\lambda_{max} = \dfrac{2898}{60}$

$\lambda_{max} = 48.3 \mu_m$

range of different spectrum

UV ----0.01-0.4

visible----0.4-0.7

infrared------0.7-100

for sun T = 5800

λ 0.01 0.4 0.7 100

λT 58 2320 4060 5.8 x 10⁵

F 0 0.125 0.491 1

fractions

for UV = 0.125

for visible = 0.441-0.125 = 0.366

for infrared = 1 -0.491 = 0.509

8 0

3 years ago

Imagine you are holding an apple. how could you increase the potential energy of this apple?

Ray Of Light [21]

If you're holding the apple at your waist, lift it to your mouth.
Potential energy relative to any level is proportional to its height
above that level. Increase that height, and you've increased the
potential energy.

Since energy is conserved ... it never magically appears or
disappears ... you need to tell where that extra energy for the
apple came from.

It's exactly the work you did ... the force of your muscles acting
through the distance you raised the apple ... that became the
additional potential energy that the apple gained.

6 0

2 years ago

A driver in a car traveling at a speed of 50 mi/h sees a deer 50 m away on the road. Calculate the minimum constant acceleration

alisha [4.7K]

Answer:

a= - 0.79 m/s²

Explanation:

Given that

Speed ,u = 20 mi/h

We know that

1 mi/h= 0.44 m/s

Therefore ,u = 8.94 m/s

Distance ,s= 50 m

Lets take the acceleration of the car = a m/s²

The final speed of the car ,v = 0 m/s

We know that

v²= u² + 2 a s

Now by putting the values

0²= 8.94² + 2 x a x 50

$a=-\dfrac{8.94^2}{2\times 50}\ m/s^2$

a= - 0.79 m/s²

Therefore the acceleration will be - 0.79 m/s².

6 0

3 years ago