Answer:
A car would need to be moving with a velocity of 28.86 m/s for its acceleration to be numerically equal to the acceleration due to gravity.
Explanation:
Radial acceleration for an object in circular motion is given by
α = v²/r
α = g = 9.8 m/s²
v = ?
r = 85 m
9.8 = v²/85
v² = 9.8 × 85 = 833
v = 28.86 m/s
Using V= vo +at with Vo = 0 and a= 4m/sec2.
V= 0+ 4x8= 32m/s
<span> force of 10.0 N
</span>
<span>distance of 0.9 m
w=f*d
w=10*0.9
=9.0 j</span>
A) When the angle between the Force (F) and Displacement (x) is 0°, because, Work done (W) is directly proportional to the Cosine of the Angle between the Force applied and the resultant displacement of the subject.
W = F•x cos ∅
If ∅ = 0°,
W = F•x ===> Maximum Work Done.
If ∅ = 45°,
W = F•x/√2
If ∅ = 90°,
W = 0
If ∅ = 180°,
W = –F•x ===> Minimum Work Done.
