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STatiana [176]
3 years ago
6

The arithmetic mean of ten boys is 8 years, 6 months one of them is 13 years old. Then the arithmetic mean of remaining 9 boys i

s
a)9.5 b) 9 c) 8 d) 7
Mathematics
1 answer:
FrozenT [24]3 years ago
3 0
<span>The arithmetic mean of ten boys is 8 years, 6 months = 8.5 years
total age = 10* 8.5 = 85 years

one of them is 13 years
total age of rest = 85 - 13 = 72 years
mean of rest = 72/9 = 8 years

Answer is C) 8 years
</span>
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Use the given pair of functions to find and simplify expressions for the following functions and state the domain of each using
Tamiku [17]

Answer:

Given functions,

f(x) = 3 - x^2

g(x) = \sqrt{x}+1

Since, by the compositions of functions,

1. (g◦f)(x) = g(f(x))

=g(3-x^2)

=\sqrt{3-x^2}+1

Since, (g◦f) is defined,

If 3 - x² ≥ 0

⇒ 3 ≥ x²

⇒ -√3 ≤ x ≤ √3

Thus, Domain = [-√3, √3]

2. (f◦g)(x) = f(g(x))

=f(\sqrt{x}+1)

=3-(\sqrt{x}+1)^2

Since, (g◦f) is defined,

If  x ≥ 0

Thus, Domain = [0, ∞)

3. (f◦f)(x) = f(f(x))

=f(3-x^2)

=3-(3-x^2)^2

=3-9-x^4+6x^2

=-6+6x^2-x^4

Since, (f◦f) is a polynomial,

We know that,

A polynomial is defined for all real value of x,

Thus, Domain = (-∞, ∞)

8 0
3 years ago
Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

6 0
3 years ago
An investor invested a total of $2500 in two mutual funds. One fund earned a 5% profit while the other earned a 3% profit. If th
7nadin3 [17]

Answer:

$500 and $2000

Step-by-step explanation:

Let x represent the total investment = $2500

also, this total is split into two different funds

Lets represent these funds as a and b, such that fund a yields a profit of 3% and fund b yield a profit of 5%

So,

a + b = x

a + b =  2500   ......eq 1

Profit from each fund gives;

0.03 a + 0.05b = 115     ....eq 2

Solve simultaneously using substitution method

From eq 1;

b = 2500 - a

Slot in this value in eq 2

0.03a + 0.05 (2500 - a) = 115

expand

0.03a + 125 - 0.05a = 115

collect like terms

0.03a - 0.05a = 115 - 125

-0.02a = -10

Divide both sides by -0.02

a =  $500

Put this value of a in eq 1

500 + b =  2500

Subtract 500 from both sides

b = 2500 - 500

b = $2000

3 0
3 years ago
Please help:)!!! thanks sm
castortr0y [4]
The answer is 12 because I just did the math
6 0
3 years ago
Someone please help me asap
cupoosta [38]

Answer:

a) 0.008

b) 0.000000009

c) 0.00004

d) 0.0000000006

5 0
3 years ago
Read 2 more answers
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