A i think, because breeding season doesn’t usually limit a population and genetic variability doesn’t really limit a population too. If its not a its either b but im pretty sure its A
Assuming independent assortment, there are three homozygous genes and two heterozygous genes. The number of gamete that can be formed from these genes = 2^ [number of hetreozygous genes] = 2^2 = 4.
The number of gamete that can be formed is 4.
I’m pretty sure it’s A
Sorry if I get it wrong but I think it’s A for sure!
The right answer is <em>Bacillus.</em>
The pH-sensitive green fluorescent dye conjugates (available for <em>E.coli</em> and <em>Staphylococcus aureus</em>), give an accurate and faster results than other phagocytosis assay.
These conjugates are non-fluorescent in the extracellular medium (at neutral pH), but fluoresce will be brightly green at acidic pH such as in phagosomes, which makes it an ideal tool for phagocytosis assay.