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lana [24]
3 years ago
12

3.16228 rounded to the nearest tenth

Mathematics
2 answers:
alina1380 [7]3 years ago
8 0

Answer:

3.2

Step-by-step explanation:

it is 3.2 because, you look at the 2nd number after the decimal and if it is 5 or larger you round up and if it is 4 or less you round down. So in this case you would be rounding up which makes the 1 a 2.  

musickatia [10]3 years ago
4 0

Answer:

3.2

Step-by-step explanation:

you have to go to the tenths place then look behind it and if that number is 5 or higher then you change the tenths place into one number higher

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Find the value of x of this question ​
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<h3><u>Let's</u><u> </u><u>understand</u><u> </u><u>the concept</u><u>:</u><u>-</u></h3>
  • Here angle B is 90°
  • So \triangle ABC and \triangle ABD Are right angled triangle
  • So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

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