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posledela
3 years ago
8

Functional groups create ____________ sites in molecules. The polar part of a molecule that can hydrogen bond to water is said b

e ____________ . Pi (π) bonds create ____________ sites and will react with electron-deficient species. A electronegative heteroatom like nitrogen, oxygen, or a halogen makes a carbon atom ____________ . The nonpolar part of a molecule that is not attracted to water is said to be ____________ . A lone pair on a heteroatom makes it basic and ____________ .
Chemistry
1 answer:
zhenek [66]3 years ago
5 0

Functional groups create reactive sites in molecules.

The polar part of a molecule that can hydrogen bond to water is said be hydrophilic.

Pi (π) bonds create active sites and will react with electron-deficient species.

A electronegative heteroatom like nitrogen, oxygen, or a halogen makes a carbon atom electrophilic.

(carbon will have less electronic density, which is attracted by the more electronegative heretoatoms, and it will tend to attract electron rich chemical species, and in this situation we say that the carbon atom is electrophilic).

The nonpolar part of a molecule that is not attracted to water is said to be hydrophobic.

A lone pair on a heteroatom makes it basic and nucleophilic.

(the heteroatom with the lone pair will tend to attract electron poor chemical species, and in this situation we say that the heteroatom is nucleophilic).

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professor190 [17]

Answer:

1.717 J/g °C  ( third option)

Explanation:

A piece of the unknown metal dropped into water this means that Q of metal is equal to Q of the water. We write this equality as follows:

<u>Step 1: writing the formulas:</u>

Q = mc∆T

⇒ -Q(metal) = Q(water)   Because :Metal dropped into water this means that Q of metal is equal to Q of the water.

<em>We can write the formula different :</em>

Mass of metal * (cmetal)(ΔT) = Mass of water *(cwater) (ΔT)

⇒ Here c is the specific heat and depends on material and phase

<em>For this case :</em>

mass of the metal  = 68.6g

mass of the water = 42g

Specific heat of the metal = TO BE DETERMINED

Specific heat of the water = 4.184J/g °C

Initial temperature of the metal = 100 °C  ⇒ Change of temperature: 52.1 - 100

Initial temperature of the water = 20°C  ⇒ Change of temperature:  52.1 - 20

<u />

<u>Step 2: Calculating specific heat of the metal</u>

-(Mass of metal) * (cmetal)*(ΔT)) = (Mass of water) *(cwater)*(ΔT)

-68.6g (cmetal)(52.1 - 100) = 42g (4.184j/g °C) (52.1 - 20)

-68.6g *cmetal * (-47.9) = 42g (4.184j/g °C) *(32.1)

3285.94 * cmetal = 5640.87

cmetal = 5640.87 / 3285.94 = 1,71667 J/g °C

cMetal = 1.717 J/g °C

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