Generally, metals GIVE AWAY their outer shell electrons, hydrogen usually GAINS an electron in order to become stable.
n the Bohr Model, the electron is treated as a particle in fixed orbits around the nucleus. In the Quantum Mechanical Model, the electron is treated mathematically as a wave. The electron has properties of both particles and waves.
The Bohr model was a one-dimensional model that used one quantum number to describe the distribution of electrons in the atom. The only information that was important was the size of the orbit, which was described by “n” the principle quantum number.
Schrodinger's model (Quantum Mechanical Model) allowed the electron to occupy three-dimensional space. It, therefore, required three coordinates, or three quantum numbers, to describe the distribution of electrons in the atom.
Answer:
i got 6
Explanation:
Because 14 feet divide by 20.5 gives you 0.6
so it 0.6 times 10 =6
Answer:
(a) -49.9 kJ/mol;
(b) To the right;
(c) 34.6 kJ/mol
Explanation:
(a) For this reaction, since it's at equilibrium and standard states, we know that we can apply the equation:
Substituting the given variables:
(b) Notice that this reaction is spontaneous, since 
. This means reaction spontaneously proceeds to the right side. Besides, K > 1, this means products dominate over reactants, so reaction proceeds to the right.
(c) Given the expression of the formation constant, we can use the same expression to calculate the reaction quotient at non-standard conditions:
![Q_f = \frac{[Ni(NH_3)_6]^{2+}}{[Ni^{2+}][NH_3]^6} = \frac{0.010}{0.0010\cdot 0.0050^6} = 6.4\cdot 10^{14}](https://tex.z-dn.net/?f=Q_f%20%3D%20%5Cfrac%7B%5BNi%28NH_3%29_6%5D%5E%7B2%2B%7D%7D%7B%5BNi%5E%7B2%2B%7D%5D%5BNH_3%5D%5E6%7D%20%3D%20%5Cfrac%7B0.010%7D%7B0.0010%5Ccdot%200.0050%5E6%7D%20%3D%206.4%5Ccdot%2010%5E%7B14%7D)
Now, notice that 
. In this case, we have an excess of the products, this means reaction will shift to the let left to restore the equilibrium.
Calculate:
Mass of solute = 25.8 g
mass solution = 212 g
% =( mass of solute / mass solution ) x 100
% = ( 25.8 / 212 ) x 100
% = 0.122 x 100
= 12.2 %
