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3 years ago

Which Venn diagram most accurately compares and contrasts plant and animal cells?

Chemistry

2 answers:

Cloud [144]3 years ago

8 0

I'm pretty sure its the first one

Explanation:

klemol [59]3 years ago

7 0

Answer:

The first one

Explanation:

I just used process of elimination. Both plant and animal cells have DNA, and that's only the first and third one. Then when you look at the third one, it says that plants don't have cytoplasm, which they do. So it has to be the first one.

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Phosphoric acid is a triprotic acid with the following pKa values:

lisabon 2012 [21]

Answer:

Mass NaH₂PO₄ = 1.920 g

Mass Na₂HPO₄ = 4.827 g

Explanation:

For a buffer solution we know its pH can be calculated from the Henderson-Hasselbach formula:

pH = pKa + log [A⁻]/[HA]

where [A⁻] and [HA] are the concentrations of the weak acid and its conjugate base in the buffer.

We want to prepare a buffer at pH 7.540 so we have chosen salts NaH₂PO₄ and Na₂HPO₄ as the weak acid and conjugate base respectively.

To calculate the mass of these salts we need to compute their ratio in the Henderson- Hasselbach equation .

Now since we are asked to determine the masses of NaH₂PO₄ and Na₂HPO₄ and we know we want to prepare 1.000 L of a 0.05 M phosphate buffer, we can setup a system of 2 equations with two unknowns from the ratio mentioned above:

pH = pKa + log [A⁻]/[HA]

7.540 = 7.198 + log[HPO₄²⁻] / [H₂PO₄ ⁻]

0.342 = log[HPO₄²⁻] / [H₂PO₄ ⁻]

taking inverse log function to both sides of this equation:

2.198 = [HPO₄²⁻] / [H₂PO₄ ⁻]

but this is also equivalent to

2.198 = mol HPO₄²⁻ / mol H₂PO₄⁻ (M = mol/V)

We also know that in 1 liter of 0.05 M phosphate, we have 0.05 total mol HPO₄²⁻ and H₂PO₄⁻ , thus

mol HPO₄²⁻ + mol H₂PO₄⁻ = 0.05 mol

2.198 = mol HPO₄²⁻ / mol H₂PO₄⁻

solving this system of equations calling x = mol HPO₄²⁻ and y = mol H₂PO₄⁻ , we have:

2.198 = x /y ⇒ x = 2.198y

x + y = 0.05

2.198y + y = 0.05

3.198 y = 0.05 ⇒ y = 0.05 / 3.198 = 0.016

x = 0.05 - 0.016 = 0.034

and the masses can be calculated from the molar masses ( 141.96 g/mol Na₂HPO₄ and 119.98 g/mol NaH₂PO₄

mol HPO₄²⁻ = 0.034 mol x 141.96 g/mol = 4.827 g

mol H₂PO₄⁻ = 0.016 mol x 119.98 g/mol = 1.920 g

6 0

3 years ago

Which of the following compounds will be most soluble in ethanol (CH3CH2OH)?hexane (CH3CH2CH2CH2CH2CH3)ethylene glycol (HOCH2CH2

jonny [76]

Answer:

Ethylene glycol

Explanation:

Solubility results when there is some kind of interaction between the solute and its solvent. In the case of ethylene glycol, it could form intermolecular hydrogen bonds with ethanol and is hence miscible with ethanol in all proportions.

6 0

3 years ago

Is density a direct or inverse function of the volume of an object?

marissa [1.9K]

The actual formula for volume for a cube is the length multiplied by the width and then multiplied by the height. Since all three measurements are the same, the formula results in the measurement of one side cubed. For the example, 5^3 is 125 cm^3. Multiply the volume by the known density, which is the mass per volume.

7 0

2 years ago

9.00 g/h to kilograms per minute

Mkey [24]

9.00g/1hr * 1kg/100g * 1hr/60min = 0.00015kg/min or 1.5 * 10^-4kg/min.

4 0

3 years ago

The freezing point of pure benzene (C₆H₆) is 5. 49 °C. The freezing point of a solution made using toluene (C₇H₈) in benzene is

Irina18 [472]

The molality of the toluene is 1.46 mol/kg.

<h3>What is molality?</h3>

The molality of a solution is its molal concentration. Molal concentration is denoted by m. It is the mol of solute dissolves in 1 Kg solvent.

The depression at freezing point is directly proportional to the molality of the solution. The equation we use for this type of problem is:

ΔT=iKm $f_m$

Where, ΔT $f_m$ is depression at freezing point, i is Van't hoff factor, m is molality and $K_f$ is the freezing point depression constant.

Toluene is a non-electrolyte and so the value of i for this is 1.

Depression at a freezing point is given as -13. $0^0$ and the $K_f$ is given as 5.12. So, we could calculate the molality of the solution using the equation written above.

Let's plug in the values in the equation:

ΔT=iKm $f_m$

-7.51 =1 x5. 12 xm

m = $\frac{7.51}{5. 12}$

m = 1.46 m

It means the molality of the solution is 1.46 mol/kg.

Hence, the molality of the solution is 1.46 mol/kg.

Learn more about the molality of the solution here:

brainly.com/question/12123356

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3 0

1 year ago