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3 years ago

Which Venn diagram most accurately compares and contrasts plant and animal cells?

Chemistry

2 answers:

Cloud [144]3 years ago

8 0

I'm pretty sure its the first one

Explanation:

klemol [59]3 years ago

7 0

Answer:

The first one

Explanation:

I just used process of elimination. Both plant and animal cells have DNA, and that's only the first and third one. Then when you look at the third one, it says that plants don't have cytoplasm, which they do. So it has to be the first one.

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Which of the following is a common agricultural use of a mineral? (2 points)

ipn [44]

The answer should be c

3 0

2 years ago

given that 32.0g sulphur contains 6.02×10^23 sulphur atoms,how many atoms are there in 2.70g of aluminum

dangina [55]

Answer:

6.022 × 10²² atoms

Explanation:

Generally 1 mol of any element contains 6.02×10^23 atoms. The number 6.022 × 10²³ is known as Avogadro's number.

Mass of Aluminium = 2.70g

Molar mass = 27g/mol

Number of moles = Mass / Molar mass = 2.70 / 27 = 0.1 mol

1 mol = 6.022 × 10²³

0.1 mol = x

x = 6.022 × 10²³ * 0.1 = 6.022 × 10²² atoms

5 0

2 years ago

This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): An analytical chemist has det

jeyben [28]

Answer:

0.054 mol O

Explanation:

<em>This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): CH₃CO₂H. An analytical chemist has determined by measurements that there are 0.054 moles of carbon in a sample of acetic acid. How many moles of oxygen are in the sample?</em>

<em />

Step 1: Given data

Chemical formula of acetic acid: CH₃CO₂H

Moles of carbon in the sample: 0.054 moles

Step 2: Establish the appropriate molar ratio

According to the chemical formula, the molar ratio of C to O is 2:2.

Step 3: Calculate the moles of oxygen in the sample

We will use the molar ratio to determine the moles of oxygen accompanying 0.054 moles of carbon.

0.054 mol C × (2 mol O/2 mol C) = 0.054 mol O

6 0

3 years ago

Which activity might help to increase the validity of this experiment?

MArishka [77]

A should be the answer because the more you test an experiment the more data you have to rely on changing the experiment would cause you to have different outcomes making the results different and unreliable so B, C, and D is not going to be the answer Hope this helps

5 0

2 years ago

How much salt (NaCl) is carried by a river flowing at 30.0 m3/s and containing 50.0 mg/L of salt

denis23 [38]

Answer:

129,600kg/day

Explanation:

The river is flowing at 30.0

1 m³ is equivalent to 1000L

flowrate of river = 30*1000 =30,000L/s

Convert L/s to litre per day by multiplying by 24*60*60

flowrate of river = 30,000 * 24*60*60 L/day

= 2,592,000,000L/day

if the river contains 50mg of salt in 1L of solution

lets find how many mg of salt Y is contained in 2,592,000,000L/day

by cross multiplying we have

Y= $\frac{2592000000*50}{1}$

Y= 129,600,000,000 mg/day

convert this value to kg/day by dividing by 1 million

Y= 129,600,000,000/1000000

Y= 129,600kg/day

3 0

2 years ago