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Travka [436]
3 years ago
5

At standard pressure the boiling point of an unsaturated nano3(aq) solution increases when

Chemistry
2 answers:
patriot [66]3 years ago
5 0

Answer:

4

Explanation:

BabaBlast [244]3 years ago
4 0
Missing question:
(1) the solution is diluted with water.
(2) some of the NaNO3(aq) solution is removed.
(3) the solution is stirred.
(4) more NaNO3(s) is dissolved in the solution.
Answer is: (4) more NaNO3(s) is dissolved in the solution.
Unsaturated solution means that more of a substance can be dissolve (in this case sodium nitrate). If more sodium nitrate is dissolved, molality of solution is increased, eo ipso boiling point of solution.
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This equation is balanced: N2+H2 -NH3 <br><br>A. True <br><br>B. False​
Makovka662 [10]
The equation N2+H2= NH3 is balanced. This is because N2 + 3H^2 ➡️ 2NH^3
8 0
3 years ago
How many moles of Fe2O3 are in 203 g of the compound?
ruslelena [56]
The equation is :
moles=mass/molar mass
so, the mass is 203 and molar mass is 159.69 
You divide the 203 by 156.69 as the equation shows
so the moles is 1.27 mol. 
6 0
3 years ago
Values for the molar mass of nitrogen, oxygen, and nitrogen dioxide molecules are given in the table below. What mass of nitroge
Gnoma [55]

Answer:

A). 92.02g

Explanation:

Equation of the reaction;

N2 (g)+ 2O2(g)------> 2NO2(g)

Note that the balanced reaction equation is the first step in solving any problem on stoichiometry. Once the reaction equation is correct, the question can be easily solved.

Reaction of one mole of nitrogen gas with two moles of oxygen gas yields two moles of nitrogen dioxide.

Mass of two moles of nitrogen dioxide= 2[14 + 2(16)] = 2[14+32]= 2[46]= 92 gmol-1

Therefore; Mass of two moles of nitrogen dioxide is 92

4 0
3 years ago
A gas mixture with a total pressure of 745 mmHg contains each of the following gases at the indicated partial pressures: CO2, 24
Setler79 [48]

<u>Answer:</u>

<u>For Part A:</u> The partial pressure of Helium is 218 mmHg.

<u>For Part B:</u> The mass of helium gas is 0.504 g.

<u>Explanation:</u>

  • <u>For Part A:</u>

We are given:

p_{CO_2}=245mmHg\\p_Ar}=119mmHg\\p_{O_2}=163mmHg\\P=745mmHg

To calculate the partial pressure of helium, we use the formula:

P=p_{CO_2}+p_{Ar}+p_{O_2}+p_{He}

Putting values in above equation, we get:

745=245+119+163+p_{He}\\p_{He}=218mmHg

Hence, the partial pressure of Helium is 218 mmHg.

  • <u>For Part B:</u>

To calculate the mass of helium gas, we use the equation given by ideal gas:

PV = nRT

or,

PV=\frac{m}{M}RT

where,

P = Pressure of helium gas = 218 mmHg

V = Volume of the helium gas = 10.2 L

m = Mass of helium gas = ? g

M = Molar mass of helium gas = 4 g/mol

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

T = Temperature of helium gas = 283 K

Putting values in above equation, we get:

218mmHg\times 10.2L=\frac{m}{4g/mol}\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 283K\\\\m=0.504g

Hence, the mass of helium gas is 0.504 g.

6 0
3 years ago
When 2.00 kJ of energy is transferred as heat to nitrogen in a cylinder fitted with a piston with an external pressure of 2.00 a
Vilka [71]

Answer: B

Explanation:

6 0
3 years ago
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