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4 years ago

At standard pressure the boiling point of an unsaturated nano3(aq) solution increases when

Chemistry

2 answers:

patriot [66]4 years ago

5 0

Answer:

Explanation:

BabaBlast [244]4 years ago

4 0

Missing question:
(1) the solution is diluted with water.
(2) some of the NaNO3(aq) solution is removed.
(3) the solution is stirred.
(4) more NaNO3(s) is dissolved in the solution.
Answer is: (4) more NaNO3(s) is dissolved in the solution.
Unsaturated solution means that more of a substance can be dissolve (in this case sodium nitrate). If more sodium nitrate is dissolved, molality of solution is increased, eo ipso boiling point of solution.

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I need help...

Aneli [31]

Answer:

1. Density of the rectangular prism is 20 g/cm3

2. A material's ability to dissolve : Soubility

3. Intensive property : A physical property that is independent of sample size.

Explanation:

Volume of Prism is calculated by :

$volume = L\times W\times H$

Length = 3 cm

Width = 2 cm

Height = 1 cm

$volume = 3\times 2\times 1$

V = 6 cm3

mass = 120 g

$Density = \frac{mass}{Volume}$

$Density = \frac{120}{6}$

Density = 20 g/cm3

Solubility :

It is the chemical property of the substance.

It shows the ability of the solute to dissolve in the solvent at a given temperature.

Intensive Properties:

These are bulk properties(Do not depend upon the amount of matter present)
They are independent of sample size.
Example : boiling point,melting point,temperature,refractive index

7 0

3 years ago

The concentration of dye in Solution A is 25.527 M. You have 13 mL of water at your disposal to make the dilutions. The solution

Lady bird [3.3K]

Answer:

38825.472 M

Explanation:

Using

C1V1=C2V2

To make solution B,

C1 = 25.527 M, V1 = 13 mL

C2 = 25.527 x 8 = 204.216 M

V2 = 13 X 12 = 156 mL

To make solution C'

C1 = 8 X 202.216 M = 1617.728

V1 = 8 X 156mL = 1248 mL

V2 = 4 X 13 = 52 mL

C2 = C1V1 / V2

=1617.728 X 1248 / 52

=38825.472 M

7 0

4 years ago

Suppose you have been given the task of distilling a mixture of hexane + toluene. Pure hexane has a refractive index of 1.375 an

rosijanka [135]

Answer:

Mole fraction of hexane in your sample is 0,746

Explanation:

Based on the information you can write the following equations:

X + Y = 1 (1)

Where X is mole fraction of hecane and Y is mole fraction of toluene

Also, based on the assumption that the refractive index of the hexane + toluene mixture varies linearly with mole fraction you can write:

1,375X + 1497Y = 1406 (2)

Replacing (1) in (2):

1,375X + 1,497(1-X) = 1,406

1,375X - 1,497X + 1,497 = 1,406

-0,122X = -0,091

X = -0,091/-0,122

X = 0,746

Thus, the mole fraction of hexane in your sample is 0,746

Also you can know the mole fraction of toluene replacing this value in (1):

0,746 - Y = 1

Y = 1-0,746

Y = 0,254

I hope it helps!

4 0

4 years ago

I need help with this ASAP PLEASE

Artemon [7]

439.3 g CO2

Explanation:

First find the # of moles of CO2 that results from the combustion of 3.327 mol C3H6:

3.227 mol C3H6 × (6 mol CO2/2 mol C3H6)

= 9.981 mol CO2

Use the molar mass of CO2 to determine the # of grams of CO2:

9.981 mol CO2 x (44.01 g CO2/1 mol CO2)

= 439.3 g CO2

5 0

3 years ago

What is the mole fraction of Ba(OH)2 in an aqueous solution that contains 22.8% Ba(OH)2 by mass?

antoniya [11.8K]

Answer:

0.03

Explanation:

22.8 g Ba(OH)2 (1 mol Ba (OH)2/ 171.34 g) = 0.133 mol Ba (OH)2

77.2 g H2O (1 mol H2O/18 g) = 4.29 mol H2O

X= molar fraction= mol Ba(OH)2/ mol total

X= 0.133/ (0.133+4.29) = 0.03

4 0

3 years ago