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oksano4ka [1.4K]
3 years ago
8

A local zoologist presents a graph of a primate population and describes the characteristics as follows:

Mathematics
2 answers:
podryga [215]3 years ago
8 0

Answer:

#3 is correct!

rodikova [14]3 years ago
8 0

Answer:

<h2>Third graph.</h2>

Step-by-step explanation:

From the given characteristics we can deduct which graph is correct.

First, the population of primates is expected to decline in the long run. This means that the graph must decrease at the end period, that let us only two options, first and third graph.

Second, the graph of the population has only one turning point, that us, it has only one point where it changes from increasing to decreasing, that only let us the third option, because the first graph has to turning point like a wave.

Therefore, the third graph is correct.

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The rules tell me to add the exponents. But I when I started algebra, I had trouble keeping the rules straight, so I just thought about what exponents mean. The " a6 " means "six copies of a multiplied together", and the " a5 " means "five copies of a multiplied together". So if I multiply those two expressions together, I will get eleven copies of a multiplied together. That is:
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3 years ago
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Need help with these show work pls
Amiraneli [1.4K]

Answer:

3. 35 adults and 420 children

4. The three numbers are 13, 52 and 16

Step-by-step explanation:

3. Let the number of adults be x.

Since there are 12 times more children than adults,

number of children= 12x

Total number of people= 12x +x

13x= 455

x= 455 ÷13

x= 35

12x= 35(12)

12x= 420

Therefore, there are 35 adults and 420 children at the play.

4. Let the first number be x.

Since the 2nd number is 4 times the first,

2nd number= 4x

Third number is 3 more than the first:

3rd number= x+3

sum of numbers= x +4x +x+3

6x +3= 81 (simplify)

6x= 81 -3 (bring constant to 1 side)

6x= 78 (simplify)

x= 78 ÷6

x= 13

Second number

= 4x

= 4(13) (subst. x=13)

= 52 (expand)

third number

= x +3

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8 0
4 years ago
A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (sec) t
solniwko [45]

Answer:

The upper confidence bound for population mean escape time is: 379.27

The upper prediction bound for the escape time of a single additional worker  is 413.64

Step-by-step explanation:

Given that :

sample size n = 26

sample mean \bar x =  371.08

standard deviation \sigma = 24.45

The objective is to calculate an upper confidence bound for population mean escape time using a confidence level of 95%

We need to determine the standard error of these given data first;

So,

Standard Error S.E = \dfrac{\sigma }{\sqrt{n}}

Standard Error S.E = \dfrac{24.45 }{\sqrt{26}}

Standard Error S.E = \dfrac{24.45 }{4.898979486}

Standard Error S.E = 4.7950

However;

Degree of freedom df= n - 1

Degree of freedom df= 26 - 1

Degree of freedom df= 25

At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

Similarly;

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 4.7950

The Margin of error = 8.18986

The upper confidence bound for population mean escape time is = Sample Mean + Margin   of  Error

The upper confidence bound for population mean escape time is =  371.08 +  8.18986

The upper confidence bound for population mean escape time is = 379.26986  \approx 379.27

The upper confidence bound for population mean escape time is: 379.27

b.  Calculate an upper prediction bound for the escape time of a single additional worker using a prediction level of 95%.

The standard error of the mean = \sigma \times \sqrt{1+ \dfrac{1}{n}}

The standard error of the mean = 24.45 \times \sqrt{1+ \dfrac{1}{26}}

The standard error of the mean = 24.45 \times \sqrt{1+0.03846153846}

The standard error of the mean = 24.45 \times \sqrt{1.03846153846}

The standard error of the mean = 24.45 \times 1.019049331

The standard error of the mean = 24.91575614

Recall that : At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

∴

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 24.91575614

The Margin of error = 42.55611149

The upper prediction bound for the escape time of a single additional worker  is calculate by the addition of

Sample Mean + Margin of Error

= 371.08 + 42.55611149

= 413.6361115

\approx 413.64

The upper prediction bound for the escape time of a single additional worker  is 413.64

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4 years ago
Determine the equation of the inverse of y = 7x + 2
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Since we are finding the inverse you switch the variable. So it is now x=7y+2 and now you solve for y. You would get x-2/7 = y for the inverse
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4 years ago
Is 2x+5y+7z a trinomial?
stich3 [128]

Answer:

yes

Step-by-step explanation:

Trinomial means the equation consists of 3 terms therefore 2x+5y+7z is a trinomial.

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3 years ago
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