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ivann1987 [24]
3 years ago
8

Right triangle LMN has vertices L(7, –3), M(7, –8), and

Mathematics
1 answer:
ololo11 [35]3 years ago
5 0
This is the translation.
M' is (-1,3)
N' is (2,3)
hope this helps

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Trevor picked 5 ⅗ pounds of cherries. He distributed them evenly into 12 containers. How many pounds of cherries were in each co
natulia [17]

Answer:

7/15

Step-by-step explanation:

For me, it is easier to take the 3/5 and put it in decimal form which is .6 and add the 5 to it, making 5.6, and then in a calculator put in 5.6 divided by 12 and you should get a big decimal that's pretty big but if you have a graphing calculator and convert that to a fraction and you should get 7/15, This is a pretty lazy way of me doing it but that's how I did it.

3 0
3 years ago
Question is down below
Bingel [31]

This is a great question!

To determine the probability with which two sweets are not the same, you would have to subtract the probability with which two sweets are the same from 1. That would only be possible if she chose 2 liquorice sweets, 5 mint sweets and 3 humburgs -

Probability( 2 Liquorice) = 12 / 20 * 11 / 19

As you can see, the first time you were to choose a Liquorice, there would be 12 out of the 20 sweets present. After taking that out however, there would be respectively 11 Liquorice out of 19 remaining. Apply the same concept to each of the other sweets -

Probability(2 Mint ) = 5 / 20 * 4 / 19,\\Probability( 2 Humbugs ) =  3/20 * 2/19

____

Calculate the probability of drawing 2 of each, add them together and subtract from one to determine the probability that two sweets will not be the same type of sweet!

1-\left(\frac{132}{380}+\frac{20}{380}+\frac{6}{380}\right) =\\\frac{111}{190}

<u><em>Thus, the probability should be 111 / 190</em></u>

5 0
3 years ago
Samantha is studying the population growth of an endangered birth. The growth can be modeled by the equation B(t) 100 + 3/5t^5 ,
solong [7]

The value of the population of the growth of an endangered birth after 5 years is 1975

<h3>How to determine the population after 5 years?</h3>

The population function is given as:

B(t) = 100 + 3/5t^5

At 5 years, the value of t is 5

So, we have

t = 5

Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5

This gives

B(5) = 100 + 3/5 * 5^5

Evaluate the exponent

B(5) = 100 + 3/5 * 3125

Evaluate the product

B(5) = 100 + 1875

Evaluate the sum

B(5) = 1975

Hence, the value of the population of the growth of an endangered birth after 5 years is 1975

Read more about exponential functions at:

brainly.com/question/2456547

#SPJ1

4 0
1 year ago
If 10% off is 20 what is 23% off?
stepan [7]
23% off is 46 because 10%is 20 so 20% is 40 and 1% is 2 because 20/10 is 2 so the answe is 46
7 0
2 years ago
Read 2 more answers
What is the product of −2/5 and −0.8? Select all that apply.
stepan [7]

Answer:

0.32

Step-by-step explanation:

You can convert -2/5 to -0.4. Then multiply them together to get 0.32. Remember that multiplying two negatives makes a positive. Hope this helps :)

7 0
2 years ago
Read 2 more answers
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