The height of the triangle if the base is 8 is 3.96 units
Given the following parameters
Base of a triangle = 8 units
Let the hypotenuse be "c"
Let the height be "h"
If the length of the hypotenuse of a right triangle is one unit more than twice the height, then;
c = 2h + 1
According to the Pythagoras theorem:
c² = b² + h²
(2h + 1)² = 8² + h²
Expand
4h²+4h+1 = 64 + h²
4h²-h² + 4h + 1 - 64 = 0
3h² + 4h - 63 = 0
Factorize the result
On factorizing, the value of the height is 2
h = 
h = 11.89/3
h = 3.96 units
Hence the height of the triangle if the base is 8 is 3.96 units
Learn more here: brainly.com/question/20545047
Answer:
ok then
Step-by-step explanation:
Answer:
x=56.89
Step-by-step explanation:
Move constant to other side
add 1
4c^2-8c=1
divide by 4 to make leading coeficient 1
c^2-2c=1/4
take 1/2 of linear coeficient and square it
-2/2=-1, (-1)^2=1
add that to both sides
c^2-2c+1=1/4+1
factor perfect squaer and add
(c-1)^2=5/4
square root both sides
c-1=+/-(√5)/2
add 1
c=1+/-(√5)/2
c=2.12 or -0.12