Answer:
.96
Step-by-step explanation:
From the diagram you can see that plane cuts each lateral face of hexagonal pyramid and do not cut the base. A hexagonal pyramid has six lateral faces. The intersection of each of these lateral faces with given cutting plane is segment. The figure which consists of these segments is hexagon. This hexagon is not the same as base and even is not similar to the base because the cutting plane is not parallel to the base.
Answer: resulting cross section is a hexagon, correct choice is option 4.
Using Vieta's Theorem, it is found that c = 72.
<h3>What is the Vieta Theorem?</h3>
- Suppose we have a quadratic equation, in the following format:

The Theorem states that:


In this problem, the polynomial is:

Hence the coefficients are
.
Since the difference of the solutions is 1, we have that:


Then, from the first equation of the Theorem:





Now, from the second equation:



To learn more about Vieta's Theorem, you can take a look at brainly.com/question/23509978
Answer:
4. C) 
3. B) 9,6 = the number of points you would increase each hour of studying; 65,8 = your score if you studied 0 hours
2. B) The events have a strong positive linear correlation.
1. C) Find the slope using the slope formula:

Step-by-step explanation:
4. (−7, 10) → 10 = 7 + 3 ☑
(−1, 4) → 4 = 1 + 3 ☑
(0, 3) → 3 = 0 + 3 ☑
(3, −2) → −2 ≠ −3 + 3; 0 ☒
3. You obviously have to plug "0" in for x to get your initial value of 65,8, which represents the minimum value of points you would receive if you never were to study, and of course, the 9,6 is the average score increased for every hour studied.
2. The correlation coefficient is 0,02, which is positive, so this would be the obvious choice.
1. You CANNOT write a linear equation without FIRST finding the rate of change [slope]. You will ALWAYS need the rate of change in order to write any linear equation.
I am joyous to assist you anytime.
Adding 2 to each value of the random variable
makes a new random variable
. Its mean would be
![E[X+2]=E[X]+E[2]=E[X]+2](https://tex.z-dn.net/?f=E%5BX%2B2%5D%3DE%5BX%5D%2BE%5B2%5D%3DE%5BX%5D%2B2)
since expectation is linear, and the expected value of a constant is that constant.
is the mean of
, so the new mean would be
![E[X+2]=10+2=12](https://tex.z-dn.net/?f=E%5BX%2B2%5D%3D10%2B2%3D12)
The variance of a random variable
is
![V[X]=E[X^2]-E[X]^2](https://tex.z-dn.net/?f=V%5BX%5D%3DE%5BX%5E2%5D-E%5BX%5D%5E2)
so the variance of
would be
![V[X+2]=E[(X+2)^2]-E[X+2]^2](https://tex.z-dn.net/?f=V%5BX%2B2%5D%3DE%5B%28X%2B2%29%5E2%5D-E%5BX%2B2%5D%5E2)
We already know
, so simplifying above, we get
![V[X+2]=E[X^2+4X+4]-12^2](https://tex.z-dn.net/?f=V%5BX%2B2%5D%3DE%5BX%5E2%2B4X%2B4%5D-12%5E2)
![V[X+2]=E[X^2]+4E[X]+4-12^2](https://tex.z-dn.net/?f=V%5BX%2B2%5D%3DE%5BX%5E2%5D%2B4E%5BX%5D%2B4-12%5E2)
![V[X+2]=(V[X]+E[X]^2)+4E[X]-140](https://tex.z-dn.net/?f=V%5BX%2B2%5D%3D%28V%5BX%5D%2BE%5BX%5D%5E2%29%2B4E%5BX%5D-140)
Standard deviation is the square root of variance, so
.
![\implies V[X+2]=(9+10^2)+4(10)-140=9](https://tex.z-dn.net/?f=%5Cimplies%20V%5BX%2B2%5D%3D%289%2B10%5E2%29%2B4%2810%29-140%3D9)
so the standard deviation remains unchanged at 3.
NB: More generally, the variance of
for
is
![V[aX+b]=a^2V[X]+b^2V[1]](https://tex.z-dn.net/?f=V%5BaX%2Bb%5D%3Da%5E2V%5BX%5D%2Bb%5E2V%5B1%5D)
but the variance of a constant is 0. In this case,
, so we're left with
, as expected.