Answer:
thermal
Explanation:
sorry if you get it wrong
Answer:
The correct option is A.
Explanation:
Following the equation of continuum, AV remains constant.
Case a
(3A)(V0) = AV1 + AV1 + AV1
3AV0 = 3AV1
V1 = V0
Case b
(A)(V0) = (A/3)V2 + (A/3)V2 + (A/3)V2 + (A/3)V2
AV0 = 4V2/3
V2 = 3/4V0
Case c
(A/2)(V0) = AV3 + AV3 + AV3
AV0/2 = 3AV3
V3 = V0/6
Case d
(3A)(V0) = 2AV4 + 2AV4
3AV0 = 4AV4
V4 = 3V0/4
Comparing all the flow speeds, V1 is the largest.
Thus, the correct option is A.
Answer:
5.1m
Explanation:
Use the fourth key equation of accelerated motion
vf^2=vi^2+2aΔd
we know vf is = 0 because that is when the ball reaches it's peak (not going up anymore)
0=vi^2+2aΔd
and we can rearrange for Δd, which is what you need
-vi^2=2aΔd
Δd = -vi^2/2a
Now we can plug in the values
Δd = -vi^2/2a
Δd = -(10m/s)^2/2(-9.8)
Δd = -100/-18.6
Δd = 5.10m
Answer:
Explanation:
frequency of radiation
= 8.54 x 10¹⁴
wave length = 3 x 10⁸ / 8.54 x 10¹⁴
= .3513 x 10⁻⁶ m
= 3513 A
Energy of this wave OR energy of each photon in eV
= 12375 / 3513
= 3.52 eV
the minimum amount of energy required = 3.52 eV.