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-Dominant- [34]
3 years ago
9

A path is traced from point A to point B by using the segments shown in the diagram. Paths are traced only upwards, to the right

, or diagonally upwards. How many different paths can be traced from A to B?

Mathematics
1 answer:
balu736 [363]3 years ago
5 0

Step-by-step answer:

If one is constrained to move to the right, or up, or diagonally upwards (i.e. remain in the first quadrant), then

there are three choices at A.

At the next position, whichever path one has taken, there are also three choices.

At the following position, there are no more choices.

Therefore, there are 3*3 = 9 different paths.

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Answer:

a. 9.5x + 6.5(x+c) < 8   when c>0

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Step-by-step explanation:

For Cinema 1:

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First of all, we will find out the condition when per person rates in both cinema are equal.

Assume x = no. of adults

y = no. of children

Rate per person in Cinema I = Rate per person in Cinema II

(9.5x + 6.5y)/(x+y)   =   8

9.5x + 6.5y = 8(x+y)

9.5x + 6.5y = 8x + 8y

9.5x-8x = 8y-6.5y

=> x = y

So rates are equal when no. of adults equals no. of children

For Cinema I to have better rates, no. of children should be atleast 1 more than the no. of adult. In this way the rate per person of Cinema I will be less than 8

Hence we form an inequality when y = x+c and c > 0

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Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.

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