Ask question

Ask question

All categories

3 years ago

11

Find csc x if sin x + cot x cos x = √3

1 answer:

never [62]3 years ago

4 0

The answer is square root of (3). The solution is listed below

$sin(x)+cot(x)cos(x)= \sqrt{3} \\ \\ 
sin(x)+ \frac{cos(x)}{sin(x)}*cos(x)= \sqrt{3} \\ \\ 
 \frac{sin^{2} x+cos^{2}x }{sin(x)}= \sqrt{3} \\ \\ 
 \frac{1}{sin(x)}= \sqrt{3} \\ \\ 
csc(x)= \sqrt{3}$

You might be interested in

3 times 4 and one half

yKpoI14uk [10]

14.5 is the answer to the equation

6 0

3 years ago

Read 2 more answers

Write this polynomial in standard form (x+2)(x+5)

oksian1 [2.3K]

Answer:

14

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the distance between A(-4,4) and B(-2,2). Round your answer to the nearest tenth.

Andrews [41]

Answer:

6.3

Step-by-step explanation:

7 0

3 years ago

Can someone help me with this

Kitty [74]

You can't see the picture, please reach out once i can see it

4 0

3 years ago

Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7, 2), and is parallel to the graph x + 3y = -5.

Elena-2011 [213]

Answer:

$B - A = -6$

Step-by-step explanation:

Given

Point: (-7,2)

x + 3y = -5

Required

Find B- - A in Ax + By = 3

To start with; we need to calculate the slope of x + 3y = -5

$x + 3y = -5$

Subtract x from both sides

$x - x + 3y = -5 - x$

$3y = -5 - x$

Divide both sides by 3

$\frac{3y}{3} = -\frac{5}{3} - \frac{x}{3}$

$y = -\frac{5}{3} - \frac{x}{3}$

The slope of the line is the coefficient of x

Slope = $- \frac{1}{3}$

The question says line Ax + By = 3 is parallel to line x + 3y = -5; This means that they have the same slope of $- \frac{1}{3}$

Having calculated the slope, next is to calculate the equation of the line using the following formula;

$m = \frac{y - y_1}{x - x_1}$

Where m is the slope; m = $- \frac{1}{3}$ ; $(x_1, y_1) = (-7,2)$

Substitute these values in the formula above; the formula becomes

$-\frac{1}{3} = \frac{y - 2}{x - -7}$

$-\frac{1}{3} = \frac{y - 2}{x +7}$

Cross Multiply

$-1(x+7) = 3(y-2)$

Open brackets

$-x - 7 = 3y - 6$

Add x to both sides

$x - x - 7 = 3y - 6 + x$

$-7 = 3y - 6 +x$

Add 6 to both sides

$-7 + 6 = 3y -6 + 6 + x$

$-1 = 3y + x$

Multipby both sides by -3

$-3(-1) = -3(3y + x)$

$3 = -9y - 3x$

$-9y - 3x = 3$

$-3x - 9y = 3$

Comparing the above to Ax + By = 3

$Ax = -3x\\A = -3$

$By = -9y\\B = -9$

$B - A = -9 - (-3)$

$B - A = -9 + 3$

$B - A = -6$

3 0

3 years ago