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KATRIN_1 [288]
3 years ago
6

What is 0.95 as a simplified fraction?

Mathematics
1 answer:
coldgirl [10]3 years ago
3 0

Answer:

19/20

Step-by-step explanation:

A "simplified fraction" in this case is the ratio of two integers.

0.95 = 95/100 (the ratio of two integers), which in turn can be simplified:

95/100 = 19/20

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Choose an SRS of 1000 men from this population. Now what is the probability that x falls within ±2 mg/dL of μ? The larger sample
anyanavicka [17]

Answer:

(a) 0.5398

(b) 0.06376

Step-by-step explanation:

Given u=118, SD = 25, n = 10

Since we are dealing with a stratified random sampling (SRS)

We use,

Z = X - U/(Sd/√n).

The required probability =

Pr(112 < Z < 114)

Pr(112< Z< 114)=Pr( Z<114) - Pr(Z<112)

=Pr [Z<(114-118)/(25/√100)] - Pr[Z<(112-118)/(25/√100)]

= Pr(Z<-1.6) - PR(Z<-2.4)

= 0.5498 - 0.00820

= 0.5398

(b) Now since we are considering the whole population of 1000 men we use

Z = (X - U)/Sd

Now we the Probability of Pr(118±2)= Pr(120, 116)

= Pr(116 < X <120)

Pr(118±2) = Pr(Z<120-118/25) - Pr(Z<116-118/25)

Pr(118±2) = Pr(Z<0.08) - Pr(Z< -0.08)

= 0.53188 - 0.46812

Pr(118±2)= 0.06376

Please note the complete form of this question was gotten through Google.

A government sample survey plans to measure the LDL (bad) cholesterol level of an SRS of 100 men aged 20 to 34. Suppose that in fact the LDL cholesterol level of all men aged 20 to 34 follows the Normal distribution with mean μ = 118 milligrams per deciliter (mg/dL) and standard deviation σ = 25 mg/dL.

(a) What is the probability that

¯¯¯

x

x takes a value between 114 and 122 mg/dL? This is the probability that

¯¯¯

x

x estimates μ within ±4 mg/dL.

(b) Choose an SRS of 1000 men from this population. Now what is the probability that

¯¯¯

x

x falls within ±4 mg/dL of μ? The larger sample is much more likely to give an accurate estimate of μ.

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(30 points) Please, if anyone can give me the answers to my Algebra 1b (semester two) cumulative exam, I'd be forever greatful e
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4( x - 3 ) - 5x ≥ -1 Can someone solve for this plz ?
satela [25.4K]

Answer:

Step-by-step explanation:

4x - 12 - 5x ≥ -1

-x - 12 ≥ -1

-x ≥ 11

x ≤ -11

4 0
3 years ago
I need answers for number 1.
kolezko [41]

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11^9

Step-by-step explanation:

6 0
3 years ago
The perimeter of a rectangle is 320mm. If its length increases by 10mm and its breadth decreases by 10mm then it its area will b
wariber [46]

Answer:

The length of the original rectangle is 73.4 mm.

The breadth of the original rectangle is 86.6 mm.

Step-by-step explanation:

Given : The perimeter of a rectangle is 320 mm. If its length increases by 10 mm and its breadth decreases by 10 mm then it its area will be 32 less.

To find : Calculate the length and breadth of the original rectangle ?

Solution :

The area of the rectangle is A=L\times B

Let the length of the rectangle be 'x'

The breadth of the rectangle be 'y'

The area is A=xy

Now, length increases by 10 mm i.e. L=x+10

breadth decreases by 10 mm i.e. B=y-10

The new area is A_n=(x+10)(y-10)

According to question,

A-A_n=32

xy-(x+10)(y-10)=32 ......(1)

The perimeter of a rectangle is 320 mm.

i.e. P=2(L+B)

320=2(x+y)

x+y=160

x=160-y .....(2)

Substitute the value of y from eqn (2) in (1),

y(160-y)-(160-y+10)(y-10)=32

160y-y^2-(170-y)(y-10)=32

160y-y^2-(180y-1700-y^2)=32

160y-y^2-180y+1700+y^2=32

1700-20y=32

20y=1732

y=\frac{1732}{20}

y=86.6

Substitute in (2),

x=160-86.6

x=73.4

The length of the original rectangle is 73.4 mm.

The breadth of the original rectangle is 86.6 mm.

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3 years ago
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