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IrinaVladis [17]
4 years ago
9

What particle is emitted in alpha radiation

Chemistry
2 answers:
Norma-Jean [14]4 years ago
4 0
The answer is Helium Nucleus. The alpha particle is what is emitted. 
mylen [45]4 years ago
3 0

<u>Answer:</u> The alpha particle is released after alpha radiation.

<u>Explanation:</u>

Alpha decay is defined as the decay process in which a heavier nucleus decays into a lighter nuclei. This decay process releases alpha particle which is also known as helium nucleus.

The general alpha decay reaction is given as:

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

The particle released will carry a mass of 4 units and carries a charge of +2 units.

Hence, the alpha particle is released after alpha radiation.

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How many molecules are there in 2.30 grams of NH3 ?
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Balance the equation by inserting coefficients as needed. equation: C 2 H 6 O+O 2 longrightarrow CO 2 +H 2 O
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The coefficients needed to balance the equation would be 2, 7, 4, and 6 respectively.

<h3>Balancing chemical equation</h3>

This requires that the number of atoms of each element is the same both on the reactant and product's sides.

Hence, the balanced equation of the reaction becomes:

2C_2 H_6 O+ 7O_2 --- > 4CO_2 +6H_2 O

Thus, the coefficient for each species would be 2, 7, 4, and 6 respectively.

More on balancing chemical equations can be found here: brainly.com/question/15052184

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A chemical reaction has an increase in entropy and a decrease in enthalpy. what is known about the spontaneity of the reaction?
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What is the name of 2NaI?
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An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure and temperature were 94.0mL,
xeze [42]

Answer: The original volume in liters was 0.0707L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.85 atm

P_2 = final pressure of gas = 456 mm Hg = 0.60 atm   (760mmHg=1atm)

V_1 = initial volume of gas = ?

V_2 = final volume of gas = 94.0 ml

T_1 = initial temperature of gas = 66^oC=273+66=339K

T_2 = final temperature of gas = 113^oF=318K  (32^0F=273K)

Now put all the given values in the above equation, we get:

\frac{0.85\times V_1}{339}=\frac{0.60\times 94.0}{318}

V_1=70.7ml=0.0707L   (1L=1000ml)

Thus the original volume in liters was 0.0707L

8 0
3 years ago
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